You first expand the brackets so
14y-15-10y
then you put the like terms together so you do 14y-10y= 4y
4y-15 which is the answer
\left[y \right] = \left[ 0\right][y]=[0] I hope helping with u
Answer: 7.3
Step-by-step explanation:
Do the parentheses first!
4-7= -3
Then, multiply -3 by 2
-3×2= -6
Next,
-6-6.7= -12.7
Then, add -12.7 to 20
-12.7+20=7.3
Your answer is 7.3
I'm guessing these are regular polygons so... here goes.... 11. angle 1 is (8-2)*180= 1080 then divide that by 8 (how many angles there are ) to get 135. angle 2 is 360/8 (the sum of the exterior angle is always 360) which is 45 and multiply it by 2 (because the two polygons are stuck together) to get 90.
12. it says 2 squares so angle 4 is definitely 90. angles 3 and 5 would be 45 because it's an isosceles right triangle meaning that 1 angle is 90 and that the total of the other two angles would be 90 as a triangle angle sum is 180 and since it's isosceles just divide 90 by 2 because the 2 angles are the same getting 45for angles 3 and 5.
13. the triangle includes 2 exterior angles so...360 divided by 8 = 45 (this is the measure of each exterior angle of the polygon)
45 x 2 cause as I said it includes 2 exterior angles to get 90. it's a triangle so 180 (the sum of angles in triangle) minus 90 to get 90. so 1 and 2 are both 45 and 3 is 90
