All categories

3 years ago

Which function is shown in the graph?

Mathematics

1 answer:

Mrac [35]3 years ago

4 0

Answer:

Option 3. y = csc ∅ is the right answer.

Step-by-step explanation:

In a function y = cosec ∅ we put the value of ∅ at 0,π/4,π/2,π,3π/2.

y = cosec 0 = ∞ Therefore function is not defined at ∅ = 0

y = cosec π/4 = √2 = 1.41

y = cosec π/2 = 1

y = cosec π = ∞ not defined

y = cosec 3π/2 = -1

y = cosec 2π = ∞ again not defined

While analyzing the value of expression we can say that the graph is of y = cosec ∅.

Similarly if we analyze other expressions for the values of ∅ then the graph will not match.

You might be interested in

April invested in a lifetime annuity that begins payments at age 65. Her life expectancy is 89. April invested a $1,000,000 into

Mila [183]

Answer:

Monthly payment is $5970

Step-by-step explanation:

Given : April invested in a lifetime annuity that begins payments at age 65. Her life expectancy is 89. April invested a $1,000,000 into the annuity, which earns 4.4% APR compounded monthly.

To find : what is April's monthly payment amount?

Solution :

Formula of monthly payment

Monthly payment, $M=\frac{\text{Amount}}{\text{Discount factor}}$

Discount factor $D=\frac{1-(1+i)^{-n}}{i}$

Where, Amount = $1,000,000

Rate r= 4.4%=0.044 compounded monthly

$i=\frac{0.044}{12}=0.004$

Time = 89-65=23 years

$n=23\times12=276$

Now, put all the values we get,

$D=\frac{1-(1+i)^{-n}}{i}$

$D=\frac{1-(1+0.004)^{-276}}{0.004}$

$D=\frac{1-(1.004)^{-276}}{0.004}$

$D=\frac{1-0.33}{0.004}$

$D=\frac{0.67}{0.004}$

$D=167.5$

Monthly payment, $M=\frac{\text{Amount}}{\text{Discount factor}}$

$M=\frac{1000000}{167.5}$

$M=5970.1$

Approximately,monthly payment is $5970

4 0

4 years ago

Read 2 more answers

this is kinda confusing but it says “if 1 cm represents 2 meters, how long would each measurement be on an actual basketball cou

frosja888 [35]

Answer:

28 m
15 m
24.8 m
1.0 m

Step-by-step explanation:

The given statement is the scale factor:

$\dfrac{\text{scale distance}}{\text{actual distance}}=\dfrac{1\text{ cm}}{2\text{ m}}$

This can be rearranged to the formula ...

$\text{actual distance}=\text{(scale distance)}\dfrac{2\text{ m}}{1\text{ cm}}$

Filling in the given scale distances, you find the actual distances to be ...

$\textbf{(a) }(14\text{ cm})\dfrac{2\text{ m}}{1\text{ cm}}=14\cdot2\text{ m}=28\text{ m}\\\\\textbf{(b) }(7.5\text{ cm})\dfrac{2\text{ m}}{1\text{ cm}}=7.5\cdot2\text{ m}=15\text{ m}\\\\\textbf{(c) }(12.4\text{ cm})\dfrac{2\text{ m}}{1\text{ cm}}=12.4\cdot2\text{ m}=24.8\text{ m}\\\\\textbf{(d) }(0.5\text{ cm})\dfrac{2\text{ m}}{1\text{ cm}}=0.5\cdot2\text{ m}=1.0\text{ m}\\\\$

4 0

3 years ago

What is 1 & 5/7 times 2 & 3/4

VARVARA [1.3K]

The solution of $1\frac{5}{7} \times 2\frac{3}{4}$ is $\frac{33}{7} \text{ or } 4.714$

<em><u>Solution:</u></em>

Given that we have to find the solution of given expression

Given expression is:

$1\frac{5}{7} \times 2\frac{3}{4}$

Let us first convert the mixed fraction to improper fraction

Multiply the whole number part by the fraction's denominator.

Add that to the numerator.

Then write the result on top of the denominator.

Therefore,

$1\frac{5}{7} = \frac{1 \times 7+5}{5} = \frac{12}{5}$

$2\frac{3}{4} = \frac{2 \times 4+3}{4}=\frac{11}{4}$

Now the expression becomes,

$1\frac{5}{7} \times 2\frac{3}{4} = \frac{12}{7} \times \frac{11}{4}$

Solve and simplify the above expression

$1\frac{5}{7} \times 2\frac{3}{4} = \frac{12}{7} \times \frac{11}{4} = \frac{33}{7}\\\\1\frac{5}{7} \times 2\frac{3}{4} = \frac{33}{7}$

In decimal form we get,

$\frac{33}{7}=4.714$

Thus the solution to given expression is found

5 0

4 years ago

Help me someone please

Fynjy0 [20]

The first one. The x values repeat

7 0

3 years ago

Read 2 more answers

What is a buffer made from?

Leona [35]

Answer:

Step-by-step explanation:

A buffer must contain a weak acid and its conjugate base. There are several ways a solution containing these two components can be made: Buffers can be made from weak acids or base and their salts. ... Buffers can be made from two salts that provide a conjugate acid-base pair.

8 0

3 years ago

Read 2 more answers