The constant value of $16 will remain unchanged no matter the coefficient of x being the initial deposit
<h3>Linear equations</h3>
These are equations that has a leading degree of 2. The standard linear equation is expressed as:
y = mx + b
If Lauren wrote the equation y = 3x + 16 to represent the amount of money in a bank account that starts with $16 and increases by $3 each week, the constant value of $16 will remain unchanged no matter the coefficient of x being the initial deposit
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Answer:
Let's define two transformations.
Vertical translation.
If we have a function f(x), a vertical translation of N untis is written as:
g(x) = f(x) + N
If N is positive, then the translation is upwards
If N is negative, then the translation is downwards.
Horizontal translation.
If we have a function f(x), a horizontal translation of N units is written as:
g(x) = f(x - N)
if N is positive, then the translation is to the right
If N is negative, then the translation is to the left.
Now we have a function g(x) that is a transformation of a parent function f(x) (we actually do not know which parent function, so i assume f(x) = x^2) such that we have a shift right 5 units and up 3 units.
Then:
g(x) = f(x - 5) + 3
and again, using f(x) = x^2
g(x) = (x - 5)^2 + 3
22.5 because its counting by 4.5
First simplify the square root of 1/25
-√1/25
Rewrite using the quote by rule for radicals.
-√1/√25
Any root of 1 is 1
-1/√25
Simplify the denominator. (find the square root of 25)
-1/5
The result can be shown in both exact and decimal forms.
Exact form: -1/5
Decimal form: -0.2
X= -2 and y= 2 should be those lines based on the diagram shown
hmu with brainliest <3
