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gavmur [86]
3 years ago
15

Find an equation in slope-intercept form for the line with slope -3/4 and y-intercept=0? will give BRAINLIEST

Mathematics
2 answers:
nata0808 [166]3 years ago
6 0

Answer:

Step-by-step explanation:

See the solution process below:

Explanation:

The slope-intercept form of a linear equation is:  y =mx+b

Where  m is the slope and b

is the y-intercept value.

We are given the slope in the problem so we can substitute

−5/6 for  m  in the formula.

And,

(0,6)

is the y-intercept so we can substitute

6

for

b

in the formula giving:

y

=

−

5

6

x

+

6

fgiga [73]3 years ago
4 0

Answer:

y=-3/4x

Step-by-step explanation:

y=mx+b

If the y-intercept is 0 then the b in y=mx+b is 0.

the slope is -3/4 so mx is going to be -3/4x.

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2 years ago
20 POINTS
RUDIKE [14]

<em>The correct expressions are as follows:</em>

7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} Equivalent 343

7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} Not Equivalent 49

7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} Equivalent 7^{\frac{1}{5}} \cdot 7^{\frac{14}{5}}

7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} Not Equivalent 49^{\frac{2}{10}} \cdot 7^{\frac{1}{5}}

\texttt{ }

<h3>Further explanation</h3>

Let's recall following formula about Exponents and Surds:

\boxed { \sqrt { x } = x ^ { \frac{1}{2} } }

\boxed { (a ^ b) ^ c = a ^ { b . c } }

\boxed {a ^ b \div a ^ c = a ^ { b - c } }

\boxed {\log a + \log b = \log (a \times b) }

\boxed {\log a - \log b = \log (a \div b) }

<em>Let us tackle the problem!</em>

\texttt{ }

7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} = 7^{\frac{1}{5}} \cdot (7^2)^{\frac{7}{5}}

7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} = 7^{\frac{1}{5}} \cdot (7)^{2\times \frac{7}{5}}

7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} = \boxed{7^{\frac{1}{5}} \cdot 7^{\frac{14}{5}}}

7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} = 7^{\frac{1}{5} + \frac{14}{5}}

7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} = 7^{\frac{15}{5}}

7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} = 7^{3}

7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} = \boxed{343}

\texttt{ }

<em>From the results above, it can be concluded that the correct statements are:</em>

7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} Equivalent 343

7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} Not Equivalent 49

7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} Equivalent 7^{\frac{1}{5}} \cdot 7^{\frac{14}{5}}

7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} Not Equivalent 49^{\frac{2}{10}} \cdot 7^{\frac{1}{5}}

\texttt{ }

<h3>Learn more</h3>
  • Coefficient of A Square Root : brainly.com/question/11337634
  • The Order of Operations : brainly.com/question/10821615
  • Write 100,000 Using Exponents : brainly.com/question/2032116

<h3>Answer details</h3>

Grade: High School

Subject: Mathematics

Chapter: Exponents and Surds

Keywords: Power , Multiplication , Division , Exponent , Surd , Negative , Postive , Value , Equivalent , Perfect , Square , Factor.

4 0
4 years ago
Read 2 more answers
The result of which expression will best estimate the actual product of (-4/5)(3/5)(-6/7)(5/6)​
Pachacha [2.7K]

Answer:

\frac{12}{35}

Step-by-step explanation:

\frac{-4}{5} * \frac{3}{5}  * (\frac{-6}{7} ) * \frac{5}{6}

\frac{(-4) * 3}{5 * 1} * \frac{(-1)}{7} \\\\\frac{12}{35}

5 0
3 years ago
Darren wins a coupon for $4 off the lunch special for each of 5 days. He pays $75 for his 5 lunch specials. Write and solve the
blsea [12.9K]

Answer:

19

Step-by-step explanation: (75/5) + 4= p

15+4=p

19=p

6 0
2 years ago
Read 2 more answers
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