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3 years ago

A recipe for includes:

Mathematics

1 answer:

bezimeni [28]3 years ago

5 0

Answer:

$\frac{1}{4} ,\frac{2}{3} ,\frac{3}{4} ,\frac{3}{8}$

Step-by-step explanation:

Let

$w$ be number of cumin servings
$x$ be number of cups coconut milk
$y$ be number of cups of tofu
$z$ be number of cups of vegetable stock

every serving must be halved and represented as simple fraction

⇒

$w_{new}=\frac{w}{2}=\frac{1}{2\times2}=\frac{1}{4}$

$x_{new}=\frac{x}{2}=\frac{4}{3\times2}=\frac{2}{3}$

$y_{new}=\frac{y}{2}=\frac{3}{2\times2}=\frac{3}{4}$

$z_{new}=\frac{z}{2}=\frac{3}{4\times2}=\frac{3}{8}$

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The fencing of the left border costs $4 per foot, while the fencing of the lower border costs $1 per foot. (no fencing is requir

lord [1]

Answer 
Left border = 8 feet
Lower border =32 feet
Area=128 〖ft〗^2

Explanation 
The area is a right triangle.
Let us take the left border to be y feet and the lower border to be x feet
Area=1/2 yx
The cost of fencing would be 4y+x=64.
From this expression x=64-4y
Substituting this value of x in the area we have;
Area=1/2 y(64-4y)
A=32y-2y^2
To get the maximum area of the triangle the first derivative of the area would te equal to zero.
A=32y-2y^2
dA/dy=32-4y=0
4y=32
y=8
Since x=64-4y
x=64-(4×8)=32
The dimensions of the garden are 8 feet by 32 feet.
Since the garden is a right triangle,
Area=1/2×8×32
Area=128 〖ft〗^2

3 0

3 years ago

What is −5/8÷9/10 ?−25/36−9 1/6−35/80−1 3/6

balandron [24]

Answer:

-25/36

Step-by-step explanation:

7 0

3 years ago

I really need help guys can some one plz help me it's for 10 points

11111nata11111 [884]

Answer:

$\sqrt{8}----- 2units,2units$

$\sqrt{7} ------\sqrt{5}units,\sqrt{2}units$

$\sqrt{5}-------1unit,2units$

$3------2units, \sqrt{5}units$

Step-by-step explanation:

Use pythagorean's theorem to solve each pair individually.

The instructions say that you have the two sides (a and b) and you have to match it with their hypothenuse.

$Formula: c^2=a^2+b^2$

1. $a=\sqrt{5}, b=\sqrt{2}$

Plug this into the formula.

$c=\sqrt{(\sqrt{5} )^2+(\sqrt{2})^2 }$

The square here eliminates the roots.

$c=\sqrt{5+2}\\ c=\sqrt{7}$

2. $a=\sqrt{3}, b=4$

$c=\sqrt{(\sqrt{3} )^2+(4)^2}\\ c=\sqrt{3+16}\\ c=\sqrt{19}$

3. $a=2, b=\sqrt{5}$

$c=\sqrt{(2)^2+(\sqrt{5})^2 }\\ c=\sqrt{4+5}\\ c=\sqrt{9}\\ c=3$

4. $a=2, b=2$

$c=\sqrt{(2)^2+(2)^2}\\ c=\sqrt{4+4}\\ c=\sqrt{8}$

5. $a=1, b=2$

$c=\sqrt{(1)^2+(2)^2}\\ c=\sqrt{1+4}\\ c=\sqrt{5}$

7 0

3 years ago

In how many distinguishable ways can you arrange the letters in the word CONNECTICUT? *

borishaifa [10]

Answer:

The number of distinguishable arrangements are 1,663,200.

Step-by-step explanation:

The word is: CONNECTICUT

The number of ways to arrange a word when no conditions are applied is:

$\frac{n!}{k_{1}!\cdot k_{2}!\cdot k_{3}!...\cdot k_{n}!}$

Here k is the number of times a word is repeated.

In the word CONNECTICUT there are:

3 Cs

2 Ns

2 Ts

And there are a total of n = 11 letters

So, the number of distinguishable arrangements are:

$\frac{n!}{k_{1}!\cdot k_{2}!\cdot k_{3}!...\cdot k_{n}!}=\frac{11!}{3!\times 2!\times 2!}$

$=\frac{39916800}{6\times 2\times 2}\\\\=1663200$

Thus, the number of distinguishable arrangements are 1,663,200.

7 0

3 years ago

If I Row my canoe at 5 mph and I travel upstream at 3 mph, how fast will I be traveling downstream if I am rowing at the same ra

Assoli18 [71]

Is the same as the one you just did.

keep in mind that, going against the current, the current's speed erodes speed from your regular speed, whilst if you're going with the current, the current's speed adds to it.

now, in this case, you row 5mph, going upstream you're only doing 3mph, whatever happened to the other 2mph? well, the current speed eroded them, meaning the speed of the river is 2mph.

now, going downstream with the current, your regular speed is 5mph, and the current is 2mph, since the current adds to yours, then you're going 5 + 2, mph.

5 0

3 years ago