What is the midpoint of the segment shown below?

solving systems of equations by graphing/given the system of equations and their graphs. identify the solution

ipn [44]

Answer:

(-2,-3)

hope it will help you

7 0

3 years ago

Explain the differences (exponents)<br><br> -6^4 and (-6)^4

wel

Step-by-step explanation:

$- {6}^{4} = - 1296 \\ \\ (- {6})^{4} = 1296$

The product of $-6^4$ is negative whereas the product of $(-6) ^4 is positive.$

7 0

3 years ago

What is the value of x?<br><br> Please help! Thanks!

leonid [27]

Answer:

x=75

Step-by-step explanation:

We can use proportions to solve this problem. Put the side of the small triangle over the side of the large triangle.

42 50

------ = ----------

42+63 50+x

42 50

------ = ----------

105 50+x

Using cross products

42(50+x) = 50*(105)

2100+42x = 5250

Subtract 2100 from each side

2100-2100+42x = 5250-2100

42x =3150

Divide by 42

42x/42 = 3150/42

x = 75

8 0

4 years ago

This is due today, and I have no idea what I'm doing, please help if you know anything.

defon

Binomial distribution formula: P(x) = (n k) p^k * (1 - p)^n - k

a) Probability that four parts are defective = 0.01374

P(4 defective) = (25 4) (0.04)^4 * (0.96)^21

P(4 defective) = 0.01374

b) Probability that at least one part is defective = 0.6396

Find the probability that 0 parts are defective and subtract that probability from 1.

P(0 defective) = (25 0) (0.04)^0 * (0.96)^25

P(0 defective) = 0.3604

1 - 0.3604 = 0.6396

c) Probability that 25 parts are defective = approximately 0

P(25 defective) = (25 25) (0.04)^25 * (0.96)^0

P(25 defective) = approximately 0

d) Probability that at most 1 part is defective = 0.7358

Find the probability that 0 and 1 parts are defective and add them together.

P(0 defective) = 0.3604 (from above)

P(1 defective) = (25 1) (0.04)^1 * (0.96)^24

P(1 defective) = 0.3754

P(at most 1 defective) = 0.3604 + 0.3754 = 0.7358

e) Mean = 1 | Standard Deviation = 0.9798

mean = n * p

mean = 25 * 0.04 = 1

stdev = $\sqrt{np(1-p)}$

stdev = $\sqrt{(25)(0.04)(1-0.04)}$ = 0.9798

Hope this helps!! :)

7 0

3 years ago

A trapezoid is broken into 2 triangles and 1 rectangle. The triangles both have a base of 2 meters and a height of 5 meters. The

Lemur [1.5K]

Answer:

Part 1) The trapezoid has an area of $20\ m^2$

Part 2) The kite has an area of $21\ m^2$

Part 3) The area of the trapezoid is less than the area of the kite

Step-by-step explanation:

Part 1

Find the area of trapezoid

we know that

The area of trapezoid is equal to the area of two congruent triangles plus the area of a rectangle

so

$A=2[\frac{1}{2} (2)(5)]+(2)(5)$

$A=10+10=20\ m^2$

Part 2

Find the area of the kite

we know that

The area of the kite is equal to the area of two congruent triangles

so

$A=2[\frac{1}{2} (7)(3)]=21\ m^2$

Part 3

Compare the areas

The trapezoid has an area of $20\ m^2$

The kite has an area of $21\ m^2$

so

$20\ m^2< 21\ m^2$

therefore

The area of the trapezoid is less than the area of the kite

5 0

4 years ago

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