The value of c to complete the square is one. In order to find the c value you divide the b value (-2) by 2 (-1) and then square that. -1 squared is 1. This can then be easily factored into (x-1)^2
1). 16 Y= 164. ( then divided)
Y= 164 : 16
Y= 41 : 4
Y = 10 +1/4
2) 8z = 64. (then divided)
z= 64 :8
z= 8
3. D = A•B•C. ( divided)
D : A•B = C
C= D:AB
c. c= d divided by ab
How many faces does the spinner has
<h3>
Answer: B) Only the first equation is an identity</h3>
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I'm using x in place of theta. For each equation, I'm only altering the left hand side.
Part 1
cos(270+x) = sin(x)
cos(270)cos(x) - sin(270)sin(x) = sin(x)
0*cos(x) - (-1)*sin(x) = sin(x)
0 + sin(x) = sin(x)
sin(x) = sin(x) ... equation is true
Identity is confirmed
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Part 2
sin(270+x) = -sin(x)
sin(270)cos(x) + cos(270)sin(x) = -sin(x)
-1*cos(x) + 0*sin(x) = -sin(x)
-cos(x) = -sin(x)
We don't have an identity. If the right hand side was -cos(x), instead of -sin(x), then we would have an identity.
5 and hello fellow k12 student isn't that a question from the unti test or am I wrong just asking let me know if this help. you add all the numbers them divide byt how many number there are so 40/8 was 5 make sure to put the gegative sign in front of it can mess up the answer. FORGIVE ME IF THE ANSWER'S WRONG.