Answer:
a) P=0.2503
b) P=0.2759
c) P=0.3874
d) P=0.2051
Step-by-step explanation:
We have this information:
25% of American households have only dogs (one or more dogs)
15% of American households have only cats (one or more cats)
10% of American households have dogs and cats (one or more of each)
50% of American households do not have any dogs or cats.
The sample is n=10
a) Probability that exactly 3 have only dogs (p=0.25)
b) Probability that exactly 2 has only cats (p=0.15)
c) Probability that exactly 1 has cats and dogs (p=0.1)
d) Probability that exactly 4 has neither cats or dogs (p=0.5)
Answer:
9.647 x 10 to the 7th
Step-by-step explanation:
that's the answer
Answer:
0.1105
Step-by-step explanation:
We know that question about reporting a cheating is asked to 172 students.
So the sample size would be n=172.
Out of 172 undergraduate students only 19 students answered "yes". It means that only 19 out of 172 students are willing to report cheating and so x=19.
According to definition of proportion
proportion=number of favorable outcome/total number of outcome
p=x/n
we are given that x=19 and n=172 so,
p=19/172=0.1105.
Hence according to given data 11.05% of students are wiling to report cheating by other students.
