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3 years ago

Find the 50th term of the sequence 5,-2,-9,-16 ,,,

1 answer:

7 0

Common difference is -2-5 = -7
first term is 5

a_50 = 5 -7(50-1) = -338

2) d = 3 - (-7) = 10
a = -7

a_110 = -7 + 10(110 - 1) = 1083

d = -27 - (-22) = -5

second -7 - 5= -12
third = -12 - 5 = -17

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Brian needs to paint a logo using two right triangles. The dimensions of the logo are shown below. What is the difference betwee

solong [7]

Answer:

7.5 cm²

Step-by-step explanation:

Dimensions of the large ∆:

$base (b) = 3cm, height (h) = 9cm$

$Area = 0.5*b*h = 0.5*3*9 = 13.5 cm^2$

Dimensions of the small ∆:

$base (b) = 2cm, height (h) = 6cm$

$Area = 0.5*b*h = 0.5*2*6 = 6 cm^2$

Difference between the area of the large and the small ∆ = 13.5 - 6 = 7.5 cm²

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3 years ago

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Alex777 [14]

Answer:

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Step-by-step explanation:

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2 years ago

I really need help with this algebra problem:<br> 5a=89

stiks02 [169]

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3 years ago

Jane has three boxes she needs to ship. Box X weighs 33 kg more than Box Y and Box Z weighs 12 kg more than Box Y. She

andreyandreev [35.5K]

Answer:

$3w+45=557$

Step-by-step explanation:

Let the weight of box Y be w kg.

Box X weighs 33 kg more than Box Y, then the weight of box X is

$w+33$ kg.

Box Z weighs 12 kg more than Box Y, then the weight of box Z is

$w+12$ kg.

The total weight of all boxes is

$w+(w+33)+(w+12)=w+w+33+w+12=3w+45$ kg

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$3w+45=557$

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3 years ago

A ping pong ball is released from a height of 60 centimeters (cm) and bounces to a height that is 3/4 the previous height. What

Oduvanchick [21]

Answer:

H = 60(3/4)^x

Step-by-step explanation:

After each bounce, the height it reach is 3/4 the previous one.

Let the height of nth bounce be denoted as h_n and the first bounce is h_1.

We are given that h_1 = 60 cm. Following the rule in the problem, we get:

h_2 = (3/4)h_1 = (3/4)60

h_3 = (3/4)h_2 = (3/4)*(3/4)60 = 60(3/4)^2

h_4 = (3/4)h_3 = (3/4)*60(3/4)^2= 60(3/4)^3

We see that h_n = 60(3/4)^n is the formula for the height for the nth bounce. Therefore, H = 60(3/4)^x is the answer.

I hope this helps! :)

8 0

3 years ago