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GREYUIT [131]
3 years ago
14

Shaun bought a movie tickets for $11.50 each and y

Mathematics
1 answer:
Ymorist [56]3 years ago
6 0

Answer:

11.50 + 4.50y

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Consider f and c below. f(x, y) = x2 i + y2 j c is the arc of the parabola y = 2x^2 from (−1, 2) to (0, 0)
aleksley [76]

(a) If there is a scalar function f(x, y) such that ∇ f(x, y) = x² i + y² j, then

∂f/∂x = x²

∂f/∂y = y²

Integrating both of these equations with respect to x and y (respectively) gives

f(x, y) = 1/3 x³ + g(y)

f(x, y) = 1/3 y³ + h(x)

Differentiating with respect to the other variable gives

∂f/∂y = g'(y) = y²

∂f/∂x = h'(x) = x²

so it follows that

f(x, y) = 1/3 x³ + 1/3 y³ + C

for some constant C.

(b) By the gradient theorem,

\displaystyle \int_C \nabla f \cdot d\vec r = f(0,0) - f(-1,2) = \boxed{-\dfrac73}

8 0
2 years ago
What do you add to 3 4/7 to make 6??
Alla [95]
You'll need to add 2 3/7 to <span> 3 4/7 to make 6. 
3 + 2 = 5 4/7 + 3/7 = 7/7 =1 
5+1=6</span>
6 0
4 years ago
10. Both x and y vary inversely with each other. When x is 10, y is 6,which of the following is not a possible pair of correspon
elena55 [62]

9514 1404 393

Answer:

  D) 45 and 1.2

Step-by-step explanation:

The "varies inversely" relationship is described by the equation ...

  y = k/x . . . . . . y varies inversely with x (and vice versa)

The value of k can be found from known values of x and y:

  xy = k . . . . . . multiply the above equation by x

  (10)(6) = k = 60 . . . . using the given values

__

To check if a given pair of numbers satisfies ...

  y = 60/x

you can multiply them together to see if the product is 60.

  (A) 12×5 = 60

  (B) 15×4 = 60

  (C) 25×2.4 = 60

  (D) 45×1.2 = 54 . . . . . not a possible pair of corresponding values.

45 and 1.2 are not a possible solution for x and y.

8 0
2 years ago
I need answers pls I have a test right now
barxatty [35]

On question 9, x = 0.46284330

6 0
3 years ago
Write and solve an equation to find the unknown angle.
Julli [10]
There's many properties you can use to find an unknown angle.

There are too many to lists but one core example would be an isosceles triangle that has two adjacent sides and angles.

Let's say that the sides of an isosceles triangle are any number "x"

now since two sides of the triangle are the same we can add these two x's together.

x+x = 2x

now the other side of the triangle can be anything you like. We can call it 4x for this example.

now if we add them all together we'll get 4x+2x=6x

Now since the angles of a triangle add up to 180 degrees
we can equate 6x=180 leaving x to be 30.

Now since x belongs to both sides of the triangle we can say that both angles are congruent as well because the two sides of the triangle are congruent. This is a known triangle law.

Since both angles are now 30 degrees this will leave us with 2(30) = 60

now if we subtract 180 - 60 we'll get 120 which is the remainder of the 3rd angle of the side that corresponds with 4x.
 <span />
5 0
3 years ago
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