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3 years ago

What the answer to this

Mathematics

2 answers:

Tresset [83]3 years ago

8 0

Answer:

Erm

Step-by-step explanation:

JulijaS [17]3 years ago

6 0

Answer:

Step-by-step explanation:

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-4+6y=16 Change to slope (intercept)

hichkok12 [17]

*here is step by step*
(Remember to add the 'x' to the slope)

-4x+6y=16

6y=4x+16

y= 4/6x + 2.66

The complete answer is:
y= 2/3x + 2.66

7 0

3 years ago

How do i solve the system of equations by graphing? 2x+y=7 x-2y=6

scoray [572]

Answer:

Step-by-step explanation:

1. y = -2x + 7

2. Graph it (Mark (0, 7) or 7 on the y axis and go over one, down two, mark it and draw a line through both)

3. -2y = -x + 6

4. divide entire equation by 2 to isolate y

5. -y = -x + 3

6. multiply entire equation by -1 to make it positive

7. y=x+3

8. graph it (Mark (0,3) and go over one, down one, mark it and draw a line through both new points)

9. Where the lines intersect is your answer

8 0

3 years ago

What is the solution to x 4 – 12x 2 + 10 > 0?

Umnica [9.8K]

Answer: The picture contains the answer and the steps

5 0

3 years ago

<img src="https://tex.z-dn.net/?f=54x2y%20-%2012x2y2" id="TexFormula1" title="54x2y - 12x2y2" alt="54x2y - 12x2y2" align="absmid

Free_Kalibri [48]

Answer:

6x²y(9 - 2y)

Step-by-step explanation:

Step 1: Factor out GCF

6(9x²y - 2x²y²)

Step 2: Factor out x²

6x²(9y - 2y²)

Step 3: Factor out y

6x²y(9 - 2y)

And we have our factored answer.

7 0

3 years ago

Read 2 more answers

4TH TIME ASKING THIS!!! Please help me! Someone pleaseeee. I need the correct answers. I don’t want to fail

Alexeev081 [22]

Answer:

The functions are inverses; f(g(x)) = x ⇒ answer D

$h^{-1}(x)=\sqrt{\frac{x+1}{3}}$ ⇒ answer D

Step-by-step explanation:

* Lets explain how to find the inverse of a function

- Let f(x) = y

- Exchange x and y

- Solve to find the new y

- The new y = $f^{-1}(x)$

* Lets use these steps to solve the problems

∵ $f(x)=\sqrt{x-3}$

∵ f(x) = y

∴ $y=\sqrt{x-3}$

- Exchange x and y

∴ $x=\sqrt{y-3}$

- Square the two sides

∴ x² = y - 3

- Add 3 to both sides

∴ x² + 3 = y

- Change y by $f^{-1}(x)$

∴ $f^{-1}(x)=x^{2}+3$

∵ g(x) = x² + 3

∴ $f^{-1}(x)=g(x)$

∴ The functions are inverses to each other

* Now lets find f(g(x))

- To find f(g(x)) substitute x in f(x) by g(x)

∵ $f(x)=\sqrt{x-3}$

∵ g(x) = x² + 3

∴ $f(g(x))=\sqrt{(x^{2}+3)-3}=\sqrt{x^{2}+3-3}=\sqrt{x^{2}}=x$

∴ f(g(x)) = x

∴ The functions are inverses; f(g(x)) = x

* Lets find the inverse of h(x)

∵ h(x) = 3x² - 1 where x ≥ 0

- Let h(x) = y

∴ y = 3x² - 1

- Exchange x and y

∴ x = 3y² - 1

- Add 1 to both sides

∴ x + 1 = 3y²

- Divide both sides by 3

∴ $\frac{x + 1}{3}=y^{2}$

- Take √ for both sides

∴ ± $\sqrt{\frac{x+1}{3}}=y$

∵ x ≥ 0

∴ We will chose the positive value of the square root

∴ $\sqrt{\frac{x+1}{3}}=y$

- replace y by $h^{-1}(x)$

∴ $h^{-1}(x)=\sqrt{\frac{x+1}{3}}$

4 0

3 years ago