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3 years ago

Multiply and simplify: 6xy3z • 3x2yx2

Mathematics

2 answers:

sweet [91]3 years ago

8 0

The simplified answer is 18x5y4z.

DIA [1.3K]3 years ago

3 0

Answer:

$18x^{5}y^{4}z$

Step-by-step explanation:

we have

$(6xy^{3}z)(3x^{2} yx^{2})$

Group terms that contain the same variable

$(6*3)(x*x^{2}*x^{2})(y^{3}*y)(z)$

Using

$x^a\cdot x^b=x^{a+b}$

$(18)(x^{1+2+2})(y^{3+1})(z)$

$(18)(x^{5})(y^{4})(z)$

$18x^{5}y^{4}z$

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-2 + (-3) x (-8 + 4)

Ymorist [56]

Answer:

Step-by-step explanation:

-2+(-3)*(-8+4)

-2+(-3)*(-4)

-2+12

4 0

3 years ago

Read 2 more answers

HELPPP RIGHT NOW PLEASEEEEE

Nadusha1986 [10]

The value of the variable x will be 37°. Then the measure of the angle ∠QNP will be 105°.

<h3>What is an angle?</h3>

The angle is the distance between the intersecting lines or surfaces. The angle is also expressed in degrees. The angle is 360 degrees for one complete spin.

Supplementary angle - Two angles are said to be supplementary angles if their sum is 180 degrees.

The measure of angles ∠MNQ = (2x + 1)° and ∠QNP = (3x - 6)°.

Then the value of x will be

We know that the angles ∠MNQ and ∠QNP are supplementary angles. Then the value of the variable x will be

∠MNQ + ∠QNP = 180°

(2x + 1)° + (3x - 6)° = 180°

5x - 5° = 180°

5x = 185°

x = 37°

Then the measure of the angle ∠QNP will be

∠QNP = [3(37) - 6]°

∠QNP = 111° - 6°

∠QNP = 105°

The value of the variable x will be 37°. Then the measure of the angle ∠QNP will be 105°.

More about the angled link is given below.

brainly.com/question/15767203

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2 years ago

Write 24 over 40 in simplest form

dsp73

Three over five or 3/5

6 0

4 years ago

PLEASE HELP ME ASAP NEED IN FIVE MIN. PLEASE NO LINKS OR FILES. I WILL MARK BRIANYLEST AND I AM GIVEING 10 EXTRA PIONTS AS WELL.

grigory [225]

Answer:

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Step-by-step explanation:

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3 years ago

Use the formula h(t)=−16t2+v0t+h0 , where v0 is the initial velocity and h0 is the initial height. How long will it take for the

Rama09 [41]

Question:

Britney throws an object straight up into the air with an initial velocity of 27 ft/s from a platform that is 10 ft above the ground. Use the formula h(t)=−16t2+v0t+h0 , where v0 is the initial velocity and h0 is the initial height. How long will it take for the object to hit the ground?

1s 2s 3s 4s

Answer:

It takes 2 seconds for object to hit the ground

Solution:

The given equation is:

$h(t) = -16t^2 + v_0t+h_0$

Initial velocity = 27 feet/sec

$h_0 = 10\ feet$

Therefore,

$h(t) = -16t^2 +27t+10$

At the point the object hits the ground, h(t) = 0

$-16t^2 +27t+10 = 0\\\\16t^2-27t-10=0$

Solve by quadratic formula,

$\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\mathrm{For\:}\quad a=16,\:b=-27,\:c=-10:\quad \\\\t=\frac{-\left(-27\right)\pm \sqrt{\left(-27\right)^2-4\cdot \:16\left(-10\right)}}{2\cdot \:16}\\\\t = \frac{27 \pm \sqrt{1369}}{32}\\\\t = \frac{27 \pm 37}{32}\\\\We\ have\ two\ solutions\\\\t = \frac{27+37}{32}\\\\t = \frac{64}{32}\\\\t = 2\\\\And\\\\t = \frac{27-37}{32}\\\\t = -0.3125$

Ignore, negative value

Thus, it takes 2 seconds for object to hit the ground

7 0

3 years ago