Answer:
More information is needed, maximum weekly profit is $1750.
Step-by-step explanation:
The maximum profit would assume Burger King does not sell any burgers on Friday, therefore all 500 burgers were sold at $3.50. 500*$3.50 = $1750 in maximum earnings for the week. More information is needed about the split between the burgers sold over the week.
Maybe the question was trying to say 500 burgers were sold on Friday. In that case, assuming every customer got three burgers, 500/3 = 166.6 customers, rounding down because you cannot have half a customer, 166 customers on Friday. Each customer paid for two burgers 166*2*$3.50 = $1162 in earnings on Friday.
Answer:
345.6
Step-by-step explanation:
Answer:
The N value represents a standard value of energy required to penetrate 30 cm into soil by percussion drilling. It is standardized as the energy of a falling hammer from a height of 0,76 m.
Step-by-step explanation:
The maximum value of the objective function is 330
<h3>How to maximize the
objective function?</h3>
The given parameters are:
Max w = 5y₁ + 3y₂
Subject to
y₁ + y₂ ≤ 50
2y₁ + 3y₂ ≤ 60
y₁ , y₂ ≥ 0
Start by plotting the graph of the constraints (see attachment)
From the attached graph, we have:
(y₁ , y₂) = (90, -40)
Substitute (y₁ , y₂) = (90, -40) in w = 5y₁ + 3y₂
w = 5 * 90 - 3 * 40
Evaluate
w = 330
Hence, the maximum value of the function is 330
Read more about objective functions at:
brainly.com/question/26036780
#SPJ1
Answer: a) 0.9980, b) 0.0013, c) 0.0020, d) 0.00000026, e) 0.0318
Step-by-step explanation:
Problem 8-4 A computer time-sharing system receives teleport inquiries at an average rate of .1 per millisecond. Find the probabilities that the number of inquiries in a particular 50-millisecond stretch will be:
Since we have given that

Using the poisson process, we get that
(a) less than or equal to 12
probability= 
(b) equal to 13
probability=

(c) greater than 12
probability=

(d) equal to 20
probability=

(e) between 10 and 15, inclusively
probability=
Hence, a) 0.9980, b) 0.0013, c) 0.0020, d) 0.00000026, e) 0.0318