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love history [14]
3 years ago
6

Is 4/8 greater or less than 4/6

Mathematics
1 answer:
IrinaK [193]3 years ago
5 0
Find the lowest common multiple=
8= 8,16,24,32,40,48
6=6,12,18,24,30,36
the lowest common multiple is 24 so then
4/8>>>>?/24 you times 8 by 3 to get 24 so you times 4 by 3 which equals 12 so it would be 12/24 (or a half)
then
4/6>>>>?/24 you times 6 by 4 to get 24 so you times 4 by 4 which equals 16 so it would be 16/24

12/24(4/8) is greater or less than 16/24(4/6)
it is less than. :)

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Burger King sells burgers for $3.50 per burger. On Fridays, you can buy 2 burgers and get 1 free. They sold 500 burgers in 1 wee
faust18 [17]

Answer:

More information is needed, maximum weekly profit is $1750.

Step-by-step explanation:

The maximum profit would assume Burger King does not sell any burgers on Friday, therefore all 500 burgers were sold at $3.50. 500*$3.50 = $1750 in maximum earnings for the week. More information is needed about the split between the burgers sold over the week.

Maybe the question was trying to say 500 burgers were sold on Friday. In that case, assuming every customer got three burgers, 500/3 = 166.6 customers, rounding down because you cannot have half a customer, 166 customers on Friday. Each customer paid for two burgers 166*2*$3.50 = $1162 in earnings on Friday.

8 0
2 years ago
PLZ HELP IM BEGGING <br><br> Find the volume of this prism
Ray Of Light [21]

Answer:

345.6

Step-by-step explanation:

3 0
2 years ago
7.2x10⁷ = (2x10⁴) (3.6x10^n) what is the value of N​
mash [69]

Answer:

The N value represents a standard value of energy required to penetrate 30 cm into soil by percussion drilling. It is standardized as the energy of a falling hammer from a height of 0,76 m.

Step-by-step explanation:

3 0
2 years ago
Max w = 5y1 + 3y2<br> s. a.<br> y1 + y2 ≤ 50<br> 2y1 + 3y2 ≤ 60<br> y1<br> , y2 ≥ 0
CaHeK987 [17]

The maximum value of the objective function is 330

<h3>How to maximize the objective function?</h3>

The given parameters are:

Max w = 5y₁ + 3y₂

Subject to

y₁ + y₂ ≤ 50

2y₁ + 3y₂ ≤ 60

y₁ , y₂ ≥ 0

Start by plotting the graph of the constraints (see attachment)

From the attached graph, we have:

(y₁ , y₂) = (90, -40)

Substitute (y₁ , y₂) = (90, -40) in w = 5y₁ + 3y₂

w = 5 * 90 - 3 * 40

Evaluate

w = 330

Hence, the maximum value of the function is 330

Read more about objective functions at:

brainly.com/question/26036780

#SPJ1

7 0
1 year ago
Problem 8-4 A computer time-sharing system receives teleport inquiries at an average rate of .1 per millisecond. Find the probab
Sphinxa [80]

Answer:  a) 0.9980, b) 0.0013, c) 0.0020, d) 0.00000026, e) 0.0318

Step-by-step explanation:

Problem 8-4 A computer time-sharing system receives teleport inquiries at an average rate of .1 per millisecond. Find the probabilities that the number of inquiries in a particular 50-millisecond stretch will be:

Since we have given that

\lambda=0.1\ per\ millisecond=5\ per\ 50\ millisecond=5

Using the poisson process, we get that

(a) less than or equal to 12

probability=  P(X\leq 12)=\sum _{k=0}^{12}\dfrac{e^{-5}(-5)^k}{k!}=0.9980

(b) equal to 13

probability= P(X=13)=\dfrac{e^{-5}(-5)^{13}}{13!}=0.0013

(c) greater than 12

probability= P(X>12)=\sum _{k=13}^{50}\dfrac{e^{-5}.(-5)^k}{k!}=0.0020

(d) equal to 20

probability= P(X=20)=\dfrac{e^{-5}(-5)^{20}}{20!}=0.00000026

(e) between 10 and 15, inclusively

probability=P(10\leq X\leq 15)=\sum _{k=10}^{15}\dfrac{e^{-5}(-5)^k}{k!}=0.0318

Hence, a) 0.9980, b) 0.0013, c) 0.0020, d) 0.00000026, e) 0.0318

6 0
2 years ago
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