First we find the common difference...to do this we subtract the first term from the second term. -7 - (-1) = -7 + 1 = -6
now we are going to find the 10th term
an = a1 + (n-1)*d <== formula for finding any term in arithmetic series
a1 = 1st term, d = common difference, n = term we want to find
now we sub
a10 = -1 + (10 -1) * -6
a10 = -1 + (9 * -6)
a10 = -1 - 54
a10 = - 55
now we will find the sum
Sn = (n (a1+ an)) / 2 <== formula for finding the sum
S10 = (10(-1 - 55))/2
S10 = (10(-56) / 2
S10 = -560/2
S10 = - 280
so the sum of the first 10 numbers is -280
324 in^2
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Answer:
3700hours
154days
Step-by-step explanation:
Speed can be defined as the distance cover per time, it can be expressed as
Speed= distance/ time........eqn(1)
Given:
distance between two planets= 4.07×10^¹²
speed of light = 1.1×10^⁹ kilometres per hour
Time= ??
Then substitute the values into equation (1) we have
Speed= distance/ time
1.1×10^⁹ kilometres per hour= 4.07×10^¹²kilometre/ time
Cross multiply, we have
Time= (4.07×10^¹²kilometre) /(1.1×10^⁹ kilometres per hour)
Time= 3700hours.
To convert to day, we know that
60 minute= 1hour
24hour=1day
Time= (3700hour×1day)/24hour
Time= 154days approximately.
Hence, the time taken for light to travel from one of these planets to the other is 154days or 3700hours
Answer:
AC
Step-by-step explanation:
First, let's find m∠B and m∠C by solving for x. Since the sum of interior angles in a triangle is 180°, we know that:
60 + 3x - 2 + 2x + 7 = 180
5x + 65 = 180
5x = 115
x = 23° so m∠B = 3(23) - 2 = 67° and m∠C = 2(23) + 7 = 53°. The longest side of a triangle is always opposite to the largest angle of the triangle, and since m∠B is the largest, we know that the side opposite to ∠B is the longest. That side is AC.
Step-by-step explanation:
let number be x
5x = 12
12 - 4x = -36
