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densk [106]
3 years ago
13

A set of final examination grades in a calculus course was found to be normally distributed with a mean of 69 and a standard dev

iation of 9. What percentage of students scored between 65 and 89?

Mathematics
1 answer:
Lady bird [3.3K]3 years ago
7 0

Answer: 66%

Step-by-step explanation:

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Step-by-step explanation:

Try using formulas such as 1

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How many milliliters are in 12.34 liters?
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Enter the simplified form of the complex fraction in the box. Assume no denominator equals zero.
Olenka [21]

Answer:

\frac{(9-x)}{3x}

Step-by-step explanation:

we have

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step 1

Solve the numerator of the quotient

\frac{2}{x-3}-\frac{3}{x}=\frac{2x-3(x-3)}{(x-3)x}=\frac{2x-3x+9}{(x-3)x}=\frac{9-x}{(x-3)x}

step 2

substitute in the original expression

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2 years ago
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Step-by-step explanation:

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6 0
2 years ago
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