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aniked [119]
3 years ago
14

The diagram above shows a rectangle inscribed in a circle AB=10 and AC =12 caculate the total surface area of the shaded part

Mathematics
1 answer:
erastova [34]3 years ago
5 0

Answer:

71.63 \: \: \mathrm{cm^2 }

Step-by-step explanation:

Once we know the diameter of the circle, we can figure out the problem.

The diameter of the circle = The diagonal of the rectangle inscribed in the circle

To find the diagonal of the rectangle, we can use a formula.

d=\sqrt{w^2 + l^2}

The width is 10 cm and the length is 12 cm.

d=\sqrt{10^2 + 12^2}

d \approx 15.62

The diagonal of the rectangle inscribed in the circle is 15.62 cm.

The diameter of the circle is 15.62 cm.

Find the area of the whole circle.

A=\pi r^2

The r is the radius of the circle, to find radius from diameter we can divide the value by 2.

r = \frac{d}{2}

r=\frac{15.62}{2}

r=7.81

Let’s find the area now.

A=\pi (7.81)^2

A \approx 191.625

Find the area of rectangle.

A=lw

Length × Width.

A = 12 \times 10

A=120

Subtract the area of the whole circle with the area of rectangle to find area of shaded part.

191.625-120

71.625 \approx 71.63

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3/30 = n/50<br><br> n = (Blank)<br><br> Find n.
UNO [17]
<span>3/30 = n/50
</span><span>1/10 = n/50
10n = 50
n = 50/10
n=5</span>
3 0
3 years ago
(0 - -3) x (1 + 5) divided by ( 2 - -2)
ElenaW [278]

Answer:

4.5

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4 0
3 years ago
Read 2 more answers
A motorboat travels 448 kilometers in 8 hours going upstream and 440 kilometers in 5 hours going downstream. What is the rate of
liubo4ka [24]

9514 1404 393

Answer:

  • boat: 72 km/h
  • current: 16 km/h

Step-by-step explanation:

The speed difference between boat and current is the upstream rate:

  (448 km)/(8 h) = 56 km/h

The sum of speeds of boat and current is the downstream rate:

  (440 km)/(5 h) = 88 km/h

The rate of the boat is half the sum of these:

  (56 +88)/2 = 72 . . . km/h

The rate of the current is half their difference:

  (88 -56)/2 = 16 . . . km/h

The rate of the boat is 72 km/h; the rate of the current is 16 km/h.

4 0
3 years ago
Micah is writing a function that models the height a dolphin reaches when it propels itself from underwater to the surface, leap
stepladder [879]

Answer:

The dolphin will be above the surface of the water for 2 seconds.

Step-by-step explanation:

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0.

This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = a(x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\Delta}}{2*a}

x_{2} = \frac{-b - \sqrt{\Delta}}{2*a}

\Delta = b^{2} - 4ac

The height of the dolphin after t seconds is given by:

h(t) = -16t^2 + 96t - 128

According to Micha's model, how long will the dolphin be above the surface of the water?

It stays above the surface of the water between the first and the second root. Initially, it is below water, when the first time for which h(t) = 0 it crosses the surface upwards, and then the second time for which h(t) = 0 it crosses the surface downwards.

We have to find these roots. So

h(t) = -16t^2 + 96t - 128

-16t^2 + 96t - 128 = 0

Multiplying by -16

t^2 - 6t + 8 = 0

\Delta = (-6)^{2} - 4*1*8 = 36 - 32 = 4

t_{1} = \frac{-(-6) + \sqrt{4}}{2} = 4

t_{2} = \frac{-(-6) - \sqrt{4}}{2} = 2

4 - 2 = 2

The dolphin will be above the surface of the water for 2 seconds.

4 0
2 years ago
Please please help me I need to learn this for my school tmr thank u very much if you do help me !!
galben [10]

Answer:

Step 1 :

Split the figure into 3 parts

part 1: triangle with base = 7 + 2 + 6 = 15in, height = 7in

part 2 : Rectangle with breadth = 3 + 6 + 2= 11in and length 8in

Part 3 :Rectangle with breadth 2in  and length 9in

Step 2 :

find the area of each part

Area of part 1

             \frac{1}{2}  * base * height = \frac{1}{2}*15*7 = 52.5in^{2}

Area of part 2

             length * breadth = 11*8 =88in^{2}

Area of part 3

              length * breadth = 2*9 =18in^2

Total area = 52.5 + 88 + 18 = 158.5 sqaure inches

4 0
3 years ago
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