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stepladder [879]

3 years ago

15

choose the equation below that represents the line passing through the point (−2, −3) with a slope of −6. y 3 = −6(x 2) y 2 = 6(

x 3) y − 3 = −6(x − 2) y − 2 = 6(x − 3)

1 answer:

pishuonlain [190]3 years ago

7 0

Line passing through point (-2, -3) with a slope of -6 is (y - (-3)) = -6(x - (-2)) => y + 3 = -6(x + 2)

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Radical 8 plus radical 18

maxonik [38]

Answer:

5√2

Step-by-step explanation:

√8 + √18

We first have to find what is the largest perfect square that goes into √8:

4 is the largest, so therefore → √8 gives you 2√2:

Work: √4 * √2 → 2 * √2 → 2√2

Now we have to find what is the largest perfect square that goes into √18:

9 is the largest, so therefore → √18 gives you 3√2:

Work: √9 * √2 → 3 * √2 → 3√2

Because 2√2 and 3√2 have the same "base" of √2, they can be added together:

2√2 + 3√2 = 5√2 (The "bases" are to be left alone!)

7 0

3 years ago

Find ac. also find ab.

e-lub [12.9K]

Answer:

Just need points well I wish I was that smart

7 0

3 years ago

An electronics store had a 20% off sale. If a stereo originally cost $125, how much did the stereo cost during tha sale?

Alenkinab [10]

125×.20=25
125-25= $100 cost

4 0

3 years ago

Imagine there are 5 cards. They are colored red, yellow, green, white, and black. You mix up the cards and select one of them wi

iragen [17]

Step-by-step explanation:

step one:

given that the sample space is

red, yellow, green, white, and black. i.e (1+1+1+1+1)= 5

the sample size is 5

the probability of picking a colored card at random is

Pr(a colored card)= 1/5

step two:

without replacement, after the first event, the sample size is now 4

then the probability of picking a colored card at random is

Pr(a colored card)= 1/4

5 0

4 years ago

1. S(–4, –4), P(4, –2), A(6, 6) and Z(–2, 4) a) Apply the distance formula for each side to determine whether SPAZ is equilatera

Aleksandr [31]

Answer:

a) SPAZ is equilateral.

b) Diagonals SA and PZ are perpendicular to each other.

c) Diagonals SA and PZ bisect each other.

Step-by-step explanation:

At first we form the triangle with the help of a graphing tool and whose result is attached below. It seems to be a paralellogram.

a) If figure is equilateral, then SP = PA = AZ = ZS:

$SP = \sqrt{[4-(-4)]^{2}+[(-2)-(-4)]^{2}}$

$SP \approx 8.246$

$PA = \sqrt{(6-4)^{2}+[6-(-2)]^{2}}$

$PA \approx 8.246$

$AZ =\sqrt{(-2-6)^{2}+(4-6)^{2}}$

$AZ \approx 8.246$

$ZS = \sqrt{[-4-(-2)]^{2}+(-4-4)^{2}}$

$ZS \approx 8.246$

Therefore, SPAZ is equilateral.

b) We use the slope formula to determine the inclination of diagonals SA and PZ:

$m_{SA} = \frac{6-(-4)}{6-(-4)}$

$m_{SA} = 1$

$m_{PZ} = \frac{4-(-2)}{-2-4}$

$m_{PZ} = -1$

Since $m_{SA}\cdot m_{PZ} = -1$ , diagonals SA and PZ are perpendicular to each other.

c) The diagonals bisect each other if and only if both have the same midpoint. Now we proceed to determine the midpoints of each diagonal:

$M_{SA} = \frac{1}{2}\cdot S(x,y) + \frac{1}{2}\cdot A(x,y)$

$M_{SA} = \frac{1}{2}\cdot (-4,-4)+\frac{1}{2}\cdot (6,6)$

$M_{SA} = (-2,-2)+(3,3)$

$M_{SA} = (1,1)$

$M_{PZ} = \frac{1}{2}\cdot P(x,y) + \frac{1}{2}\cdot Z(x,y)$

$M_{PZ} = \frac{1}{2}\cdot (4,-2)+\frac{1}{2}\cdot (-2,4)$

$M_{PZ} = (2,-1)+(-1,2)$

$M_{PZ} = (1,1)$

Then, the diagonals SA and PZ bisect each other.

8 0

3 years ago