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kenny6666 [7]
3 years ago
5

Imagine there are 5 cards. They are colored red, yellow, green, white, and black. You mix up the cards and select one of them wi

thout looking. Then, without putting that card back, you mix up the remaining cards and select another one.
Mathematics
1 answer:
iragen [17]3 years ago
5 0

Step-by-step explanation:

step one:

given that the sample space is

red, yellow, green, white, and black. i.e (1+1+1+1+1)= 5

the sample size is 5

the probability of picking a colored card at random is

Pr(a colored card)= 1/5

step two:

without replacement, after the first event, the sample size is now 4

then the probability of picking a colored card at random is

Pr(a colored card)= 1/4

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Your friend has improved in his math class. On his first test he scored 50 points, and then he scored 53, 56, 59, and 62 points
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Answer:

Step-by-step explanation: I think you skip count by 50s or something like that. So, it has to be 64.

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3 years ago
Find the perimeter of the semicircle when diameter is 3.5 cm. (1 Point)
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● Answer:

8.995 cm

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2 years ago
Which is the greatest to least, 12 3/4, 12 3/5 and 12.7
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2 years ago
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Find the sum of the geometric. Remember to show work and explain.​
Allushta [10]

Answer:   393.75

<u>Step-by-step explanation:</u>

\sum\limits^6_1 {400\bigg(\dfrac{1}{2}\bigg)^n}\\\\n=1:\ 400\bigg(\dfrac{1}{2}\bigg)^1\quad =200\\n=2:\ 400\bigg(\dfrac{1}{2}\bigg)^2\quad =100\\n=3:\ 400\bigg(\dfrac{1}{2}\bigg)^3\quad =50\\n=4:\ 400\bigg(\dfrac{1}{2}\bigg)^4\quad =25\\n=5:\ 400\bigg(\dfrac{1}{2}\bigg)^5\quad =12.5\\n=6:\ 400\bigg(\dfrac{1}{2}\bigg)^6\quad =6.25\\.\qquad \qquad \qquad \qquad \quad \_\_\_\_\_\_\_\_\_\_\\\\.\qquad \qquad \quad \quad \text{Sum}=\large\boxed{393.75}

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3 years ago
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