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3 years ago

Write the equation of a line in y =mx+b form that has a slope of 3/4 and a y-intercept of 0.

Mathematics

1 answer:

Rus_ich [418]3 years ago

4 0

Answer:

y = ¾x

Step-by-step explanation:

y = mx + b, where

m = slope and

b = y-intercept

If slope = ¾ and y-intercept =0, the equation is

y = ¾x

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Find the area of a rectangle with side lengths 3/5 inch and 5/6 inch

Helga [31]

Answer:

15/30 0r 1/2

Step-by-step explanation:

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2 years ago

What is the solution to the system of equations? O (-6,-) O (-2, 6) O (6,2) O (-2,-6)

damaskus [11]

Answer:

Option (1)

Step-by-step explanation:

System of equations is represented by two straight lines on a graph.

And solution of the system of equations is the point of intersection of these lines.

From the graph attached, two straight lines represent the system of equations.

And the point of intersection of these lines is the solution.

Therefore, solution of the system of equations will be (-6, -2).

Option (1) will be the correct option.

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3 years ago

Read 2 more answers

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DochEvi [55]

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3 years ago

When will the equation p(b)=520(0.88)^b have a value less than 100?

yulyashka [42]

Answer:

The given equation will have value less than 100 whenever the value of b is greater than 12.89

Step-by-step explanation:

For the given equation, p(b) = 520 × $0.88^{b}$ to have a value less than 100 we can establish inequality as:

p(b) < 100

or, 520 × $0.88^{b}$ < 100

or, $\frac{520}{520}$ × $0.88^{b}$ < $\frac{100}{520}$

or, $0.88^{b}$ < $\frac{1}{5.2}$

or, ㏒ ( $0.88^{b}$ ) < ㏒ ( $\frac{1}{5.2}$ )

or, b× ㏒ 0.88 < ㏒ ( $\frac{1}{5.2}$ )

or, $\frac{log (\frac{1}{5.2}) }{log (0.88)}$ < b

or, 12.89 < b

Hence for the equation to have value less than 100, b must be greater than 12.89.

3 0

3 years ago

What is the equation of the line perpendicular to 3x+y= -8that passes through -3,1? Write your answer in slope-intercept form. S

Gekata [30.6K]

Slope intercept form of a line perpendicular to 3x + y = -8, and passing through (-3,1) is $y=\frac{1}{3} x+2$

Solution:

Need to write equation of line perpendicular to 3x+y = -8 and passes through the point (-3,1).

Generic slope intercept form of a line is given by y = mx + c

where m = slope of the line.

Let's first find slope intercept form of 3x + y = -8

3x + y = -8

=> y = -3x - 8

On comparing above slope intercept form of given equation with generic slope intercept form y = mx + c , we can say that for line 3x + y = -8 , slope m = -3

And as the line passing through (-3,1) and is perpendicular to 3x + y = -8, product of slopes of two line will be -1 as lies are perpendicular.

Let required slope = x

$\begin{array}{l}{=x \times-3=-1} \\\\ {=>x=\frac{-1}{-3}=\frac{1}{3}}\end{array}$

So we need to find the equation of a line whose slope is $\frac{1}{3}$ and passing through (-3,1)

Equation of line passing through $(x_1 , y_1)$ and having lope of m is given by

$\left(y-y_{1}\right)=\mathrm{m}\left(x-x_{1}\right)$

$\text { In our case } x_{1}=-3 \text { and } y_{1}=1 \text { and } \mathrm{m}=\frac{1}{3}$

Substituting the values we get,

$\begin{array}{l}{(\mathrm{y}-1)=\frac{1}{3}(\mathrm{x}-(-3))} \\\\ {=>\mathrm{y}-1=\frac{1}{3} \mathrm{x}+1} \\\\ {=>\mathrm{y}=\frac{1}{3} \mathrm{x}+2}\end{array}$

Hence the required equation of line is found using slope intercept form

4 0

3 years ago