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san4es73 [151]
3 years ago
10

Candy is on sale for $0.75 each. you have a coupon for $0.25 off your total purchase. Write a function rule for the cost of n pi

eces of candy.
A. C(n)0.25n-0.75
B. C(n)=0.75n-0.25
C. C(n)=1.0n
D. C(n)=0.75n
Mathematics
1 answer:
alekssr [168]3 years ago
4 0
<span>The answer is B. C(n) = 0.75n - 0.25.
Let n be the number of pieces. The price for 1 piece is $0.75. The price C for n pieces without a coupon is n * $0.75: C(n) = 0.75n. The coupon value is $0.25. So, this value must be subtracted from the total price of n pieces. Since the coupon values in independent on the number of pieces, the price C for n pieces with the coupon will be: C(n) = 0.75n - 0.25. Therefore, the correct choice is B.</span>
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Step-by-step explanation:

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2 years ago
This extreme value problem has a solution with both a maximum value and a minimum value. Use Lagrange multipliers to find the ex
velikii [3]

Answer:

The maximum value= 36

Minimum value = - 36

Step-by-step explanation:

Given that

f(x, y, z) = 8 x + 8 y + 4 z

h(x,y,z)=4 x² + 4 y² + 4 z² - 36

From Lagrange multipliers

Δf = λ Δh

Δf = < 8 ,8 , 4>

Δh = < 8 x ,8 y  , 8 z>

Δf = λ Δh

So

< 8 ,8 , 4> = < 8  λ x ,8 λ y  , 8 λ z>

8 = 8  λ x                     -------------1

8 = 8 λ y                      ----  ------2

4 = 8 λ z                    ----------------3

From equation 1 ,2 and 3

Now by putting the value of x,y and z in the following equation

4 x² + 4 y² + 4 z² = 36

4\times \dfrac{1}{\lambda^2 }+4\times \dfrac{1}{\lambda^2 }+4\times \dfrac{1}{(2\lambda)^2 }=36

\dfrac{4}{\lambda^2 }+ \dfrac{4}{\lambda^2 }+ \dfrac{1}{\lambda^2 }=36

So the value of λ is

\lambda =\pm \dfrac{1}{2}

When λ = 1/2

x = 1 / λ   , y=1 / λ   ,  z= 1 /2 λ

x= 2 , y = 2 , z=1

So

f(x, y, z) = 8 x + 8 y + 4 z

f(2, 2, 1) = 8 x 2 + 8 x 2 + 4 x 1

f(2, 2, 1) =36

When λ = - 1/2

x = 1 / λ   , y=1 / λ   ,  z= 1 /2 λ

x= - 2 , y = - 2 , z= - 1

So

f(x, y, z) = 8 x + 8 y + 4 z

f(-2, -2, -1) = 8 x (-2) + 8 x (-2) + 4 x (-1)

f(-2, -2, -1) = - 36

The maximum value= 36

Minimum value = - 36

7 0
3 years ago
Read 2 more answers
Can someone help me please
Dafna1 [17]

Answer:

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Explanation:

Fill in each option for x individually.

I)     9 \leq -10 - 4(-1)  

II)    9 \leq -10 - 4(-3)  

III)   9 \leq -10 - 4(-2)

Then, simplify the right side of each inequality.

I)    9 \leq -6

II)   9 \leq 2

III)  9 \leq -2

Each of these inequalities are flase. 9 is not less than or equal to any of these values, so the answer is none.

3 0
3 years ago
Passes through (0, -4) and (-4,5)
artcher [175]

Answer:

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Step-by-step explanation:

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