Answer:
B. 252
Step-by-step explanation:
To find the answer, you have to use the formula to calculate the number of combinations as in this case, the order in which the objects are selected doesn't matter:
nCr=n!/r!(n-r)!
n= number of sample points: 10
r= number of sample points in each combination: 5
10C5= 10!/5!(10-5)!
10C5= 10!/5!*5!
10C5= 252
According to this, the answer is that you have 252 different ways to choose your school lunch.
Answer:
19
Step-by-step explanation:
I just googled it lol
Answer:
a₂ = -3
a₃ = -1
Step-by-step explanation:
We have to insert two arithmetic means between -5 and 1
Let a₁ and b₂ be the two arithmetic means between -5 and 1
-5, a₂, a₃, 1
Here,
We know that the nth term of an Arithmetic sequence
aₙ = a₁ + (n-1)d
a₄ = -5 + (4-1)d
1 = -5 + 3d
1 + 5 = 3d
3d = 6
Dividing both sides by 2
d = 2
Also
a₂ = a₁ + (2-1)d
a₂ = -5 + d
a₂ = -5 + 2 ∵ d = 2
a₂ = -3
a₃ = a₁ + (3-1)d
a₃ = -5 + 2d
a₃ = -5 + 2(2) ∵ d = 2
a₃ = -5 + 4
a₃ = -1
Thus,
a₂ = -3
a₃ = -1
Thus, the sequence becomes:
-5, -3, -3, 1
Answer:
Point-slope form: y + 3= -1(x + 4)
Slope-intercept form: y = -1x - 7
y = m * x + b,
where:
m is the slope; and
b is the intercept of the y-axis.
