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3 years ago

What is the value of the expression 2x^3 when x=-2 and y=3

Mathematics

2 answers:

cestrela7 [59]3 years ago

8 0

Answer:

2x^3

2*-2^3

2*-8

-16

therefore answer is -16

Degger [83]3 years ago

3 0

2(-2)^3
-4^3 (followed pemdas)
-4x-4x-4= -64

( I don’t know why the y is there since it isn’t in the equation? Maybe you didn’t get the whole equation

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Evaluate: 11 + sqrt(-4 + 6×4÷3)

Murrr4er [49]

Answer:

$11+\frac{2\sqrt{15}}{3}$

Step-by-step explanation:

$11 + \sqrt{(-4 + 6\times4\div3)} \\\\11+\sqrt{\frac{-4+6\times \:4}{3}}\\\\\sqrt{\frac{-4+6\times \:4}{3}}=\frac{2\sqrt{5}}{\sqrt{3}}\\\\=11+\frac{2\sqrt{5}}{\sqrt{3}}\\\\\frac{2\sqrt{5}}{\sqrt{3}}=\frac{2\sqrt{15}}{3}\\\\=11+\frac{2\sqrt{15}}{3}$

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3 years ago

Determine the value of the expression below. 7^2-9 ---------- 3+2

makkiz [27]

Answer:

1. 7^2-9 = 40

3+2 = 5

40 / 5

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3 years ago

Two sides of a right triangle have the lengths 4 and 5. What is the product of the possible lengths of the third side? Express t

marishachu [46]

Answer:

19.2

Step-by-step explanation:

1st Case:

4 and 5 are legs of the right triangle.

Using the pythagorean therom: a^2+b^2=c^2

We can say that 4^2+5^2=x^2

16+25=x^2

41=x^2

x=√41

√41 is about 6.4

x=6.4

2nd Case

5 is the hypotenuse of the right triangle and 4 is the legs.

Using the pythagorean therom: a^2+b^2=c^2

We can say that 4^2+x^2=5^2

16+x^2=25

x^2=9

x=3

Final Step

We need to multiply the two possible lengths for x. So for case 1 the length of x was 6.4 and for case two the length was 3. 6.4*3=19.2

Anwser: 19.2

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3 years ago

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bearhunter [10]

Answer:

(a) ∠HIK and ∠GFD

Step-by-step explanation:

In this geometry, there are only two pairs of alternate exterior angles:

∠HIK and ∠GFD

∠JIK and ∠EFD

Of these, only the first pair is among the answer choices.

Alternate exterior angles are ones that are outside the parallel lines, and on opposite sides of the transversal.

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3 years ago

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Allisa [31]

Answer:

3(x-6)

Step-by-step explanation:

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4 years ago