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V125BC [204]
3 years ago
12

Kyle’s bowl of cereal has 5 blue marshmallows, 2 yellow marshmallows, 3 pink marshmallows, and 4 green marshmallows. if he picks

one marshmallow at random, what is the probability that the marshmallow is green?
Mathematics
2 answers:
Vladimir79 [104]3 years ago
8 0
To be able to answer this item, first we add up all the number of marshmallows. That is,
                                n = 5 + 2 + 3 + 4 = 14
Out of the 14 marshmallows, only 4 of which are green which will lead us to the answer to this item being equal to 4/14 or 2/7. 
pogonyaev3 years ago
8 0

Answer: The probability of picking the one marshmallow is green==\frac{2}{7}


Step-by-step explanation:

The number of green marshmallow = 4

The total number of marshmallows =5+2+3+4=14

The probability of picking the one marshmallow is green=\frac{\text{number of green marshmallows}}{\text{total marshmallows}}

⇒The probability of picking the one marshmallow is green=\frac{4}{14}=\frac{2}{7}

∴The probability of picking the one marshmallow is green==\frac{2}{7}

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gizmo_the_mogwai [7]

Answer:

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If we compare the p value and the significance level assumed \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't conclude that the height of men actually its NOT significant higher than 0.3 at 1% of signficance.  

Step-by-step explanation:

Data given and notation  

\bar X=3.1 represent the sample mean

\sigma=\sqrt{6} represent the sample standard deviation for the sample

n=47 sample size  

\mu_o =3 represent the value that we want to test

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t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is higher than 3, the system of hypothesis would be:  

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Alternative hypothesis:\mu > 3  

If we analyze the size for the sample is > 30 and we know the population deviation so is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

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