(ab² + b²a) - (-2b+a²) = ?

Dima020 [189]

Answer:

QRST becomes Q prime, R prime, S prime, T prime.

Step-by-step explanation:

Any figure that is rotated, translated or reflected on the corrdinate plane is considered a prime (as long as it is congruent (the same as, or equal to) with the original). The apostrophe stands for prime.

Ex. If you reflect triangle ABC across one of the axes, the original triangle will continue being ABC, while the reflection would be A' B' C' (or A prime, B prime, C prime). I hope this helps :)

8 0

3 years ago

What is 8 is increased to 22

SOVA2 [1]

1. What is 8 increased to 22.
I believe you want me to show you what is the interest increased from 8 to 22
Let’s start the solution process:
=> 8 is the original number and supposed to be the 100% value
=> 22 is the increased number
subtract 22 by 8 to know how much is added.
=> 22 – 8 = 14
=> 14 / 8 = 1.75
=> 1.75 * 100% = 175%
Thus, the added increased is around 175% of the original money

3 0

4 years ago

An article reports on an experiment in which each of five groups consisting of six rats was put on a diet with a different carbo

loris [4]

Answer:

H0 is rejected, Hence the true average DNA content is affected by the type of carbohydrate in the diet between samples

Step-by-step explanation:

A B C D E

2.58 2.63 2.13 2.41 2.49

∑A=2.58 ∑B=2.63 ∑C=2.13 ∑D=2.41 ∑E=2.49

A² B² C² D² E²

6.6564 6.9169 4.5369 5.8081 6.2001

∑A²=6.6564 ∑B²=6.9169 ∑C²=4.5369 ∑D²=5.8081 ∑E²=6.2001

Calculations

Group A B C D E Total

N n1=1 n2=1 n3=1 n4=1 n5=1 n=5

∑xi T1=2.58 T2=2.63 T3=2.13 T4=2.41 T5=2.49 ∑x=12.24

∑x²i 6.6564 6.9169 4.5369 5.8081 6.2001 ∑x²=30.1184

Mean xi 2.58 2.63 2.13 2.41 2.49 Total2.448

Σ Σ xij^2 = 185.4 given

Let k = the number of different samples = 5

n=n1+n2+n3+n4+n5=1+1+1+1+1=5

Overall ˉx=12.24/5 =2.448

∑x=T1+T2+T3+T4+T5=2.58+2.63+2.13+2.41+2.49=12.24----1

Correction Factor=(∑x)²/n=12.242/5=29.9635--------(2)

∑T²i/ni=(2.582/1+2.632/1+2.132/1+2.412/1+2.492/1)=30.1184------(3)

∑x²=∑x²1+∑x²2+∑x²3+∑x²4+∑x²5

=6.6564+6.9169+4.5369+5.8081+6.2001=30.1184-------(4)

ANOVA:

Step-1 : sum of squares between samples

SSB=(∑T2i/ni)-(∑x)2/n

=(3)-(2)

=30.1184-29.9635

=0.1549

Step-2 : Total sum of squares

SST=SSB-CF

= 185.4-2.488

=182.952

Step-3 : Sum of Squares Within Samples

SSW=∑x²-(∑T²i/ni)=SST- SSB=

= 182.952-0.1549=182.7971

Step-4 : variance between samples

MSB=SSB/k-1

=0.1549/4

=0.0387

Step-5 : variance within samples

MSW=SSW/n-k

=182.7971/5-5

=36.55942

Step-6 : test statistic F for one way ANOVA test

F=MSB/MSW

=0.0387/36.55942 = 0 .001058

ANOVA table

Source Sums Degrees Mean

of Variation of Squares of freedom Squares

SS DF MS F

B/w samples SSB = 0.1549 k-1 = 4 MSB = 0.0387 0.001

Within samples SSW = 0 n-k = 0 MSW = 36.55942

Total SST = 0.1549 n-1 = 4

H0 : The true average DNA content is not affected by the type of carbohydrate in the diet between samples

Ha : The true average DNA content is affected by the type of carbohydrate in the diet between samples

F(4,0) at 0.05 level of significance =0.5

As calculated F=0.001 >0.5

So, H0 is rejected, Hence the true average DNA content is affected by the type of carbohydrate in the diet between samples

6 0

3 years ago

Iftwo-thirdofa number increased by 10isequal to14,find the number

elena55 [62]

Answer:

The number is 6.

Step-by-step explanation:

Let the number be x then,

By the question,

2/3 * x + 10 = 14

2x / 3 = 14 - 10

2x / 3 = 4

Cross multiply ✖

2x = 12

x = 12/2

x = 6

Hope it helps. :)

8 0

3 years ago

the difference between two numbers is 3.if the square of the smaller number is equal to four times the larger number, find the t

sukhopar [10]

Denote the numbers x, y. so we have equations y-x=3; x^2=4y, therefore x^2-4x-12=0. so x=6, y=9 or x=-2; y=1

4 0

3 years ago

(ab² + b²a) - (-2b+a²) = ?​

(ab² + b²a) - (-2b+a²) = ?