Question

The letter tiles shown below are in bag. Without looking, I am going to draw one tile. What are my chances of NOT drawing a blue A? (p.s there are 2 blue As, 1 green A, 1 green P, 1 blue L, 1 pink O, 1 pink I, and 1 pink S)
0.25
0.15
0.75
0.6

Answer 1

I'd have to go with A

Answer 2

Number of Blue A's = 2

Number of green A = 1

Number of green P = 1

Number of Blue L = 1

Number of Pink O = 1

Number of Pink I = 1

Number of Pink S = 1

Total number of tiles in a bag = 8

Number of tiles of not drawing Blue A = Number of green A + Number of green P + Number of Blue L + Number of Pink O + Number of Pink I + Number of Pink S

Number of tiles of not drawing Blue A = 1 + 1 + 1+ 1 +1 +1 = 6

P(of Not drawing blue A ) = $\frac{Not drawing blue A }{Total number of tiles}$

P(of Not drawing blue A ) = $\frac{6}{8}$

P(of Not drawing blue A ) = 0.75