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velikii [3]
3 years ago
5

Suppose your school’s computer lab provides high-end architecture software that can be accessed from any lab computer, but a max

imum of 5 students can use it at any given time. What kind of license does it have
Computers and Technology
1 answer:
LenKa [72]3 years ago
3 0

Answer:

Multiple-user licence.

Explanation:

A multiple-user licence allows the software to be accessed by the maximum number of users specified within the licence. In this scenario, it is 5 students, the connections are concurrent, meaning at any given time there can only be five users running the software. The software can be installed on more than 5 computers, but the number of active users is limited to 5.

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At Chicago Cubs games, residents across the street from Wrigley Field can watch the game from their apartment windows. Many of t
miv72 [106K]

Answer:

There is a free-rider problem.

Explanation:

A free-rider is demonstrated as the economic problem in which the people continue to access or consume a resource without working or paying to ensure the upkeep of the resource.

As per the description, the given economic problem would be characterized as 'free-rider problem' as the resources are being consumed by the people('watch the game') without contributing a penny for it. This implies the burden on limited resources as people are not fairly paying to upkeep the resource and the resources tend to be overused or degenerated. Thus, <u>'</u><u>the free-rider'</u> problem has been demonstrated here.

7 0
3 years ago
Bulldog Holdings is a U.S.-based consumer electronics company. It owns smaller firms in Japan and Taiwan where most of its cell
GenaCL600 [577]

Answer:

The answer to the following question is the parent company subsidiary relationship.

Explanation:

This relationship exists when a company controlling another by owning the majority voting of stock.

Generally, a Parent company subsidiary relationship means the relationship which exists when a corporation indirectly or directly owns shares by possessing more than the 50 percent of the voting power of another corporation.

In Parent companies, they can either hands-off or hands-on owners of subsidiaries.

It is virtually same as the holding companies.

5 0
3 years ago
What are the first and the last physical memory addressesaccessible using
Misha Larkins [42]

Answer

For First physical memory address,we add 00000 in segment values.

For Last physical memory address,we add 0FFFF in segment values.

<u>NOTE</u>-For addition of hexadecimal numbers ,you first have to convert it into binary then add them,after this convert back it in hexadecimal.

a)1000

For First physical memory address, we add 00000 in segment value

We add 0 at the least significant bit while calculating.

          1000<u>0</u> +00000 = 1000<u>0</u> (from note)

For Last physical memory address,We add 0 at the least significant bit while calculating.

   we add 0FFFF in segment value

           1000<u>0</u> +0FFFF =1FFFF    (from note)

b)0FFF

For First physical memory address,we add 00000 in segment value

We add 0 at the least significant bit while calculating.

     0FFF<u>0</u> +00000=0FFF0 (from note)

For Last physical memory address,We add 0 at the least significant bit while calculating.

   we add 0FFFF in segment value

           0FFF<u>0</u> +0FFFF =1FFEF (from note)

c)0001

For First physical memory address,we add 00000 in segment value

We add 0 at the least significant bit while calculating.

     0001<u>0</u> +00000=00010 (from note)

For Last physical memory address,We add 0 at the least significant bit while calculating.

   we add 0FFFF in segment value

           0001<u>0</u> +0FFFF =1000F (from note)

d) E000

For First physical memory address,we add 00000 in segment value

 We add 0 at the least significant bit while calculating.

    E000<u>0</u> +00000=E0000 (from note)

For Last physical memory address,We add 0 at the least significant bit while calculating.

   we add 0FFFF in segment value

           E000<u>0</u> +0FFFF =EFFFF (from note)

e) 1002

For First physical memory address,we add 00000 in segment value

 We add 0 at the least significant bit while calculating.

    1002<u>0</u> +00000=10020  (from note)

For Last physical memory address,We add 0 at the least significant bit while calculating.

   we add 0FFFF in segment value

           1002<u>0</u> +0FFFF =2001F (from note)

6 0
3 years ago
World Book is a/an A. Social media platform. B. Textbook. C. Almanac. D. Encyclopedia.
Nadusha1986 [10]
D. Encyclopedia
Not a b or c
8 0
3 years ago
Read 2 more answers
A constructor can be overloaded with more than one function which has the same name but with what two different things
andreyandreev [35.5K]
<h2>Answer:</h2>

i. Number of parameters

ii. Type of parameters

<h2>Explanation:</h2>

When there are two or more constructors, definitely with the same name, in a given class, then the constructors are said to be overloaded. An overloaded constructor appears declared many times in a class but each time with different number of parameters and/or type of parameters.

For example, given a class Test, the following combination of constructors can exist;

i. public Test(int x){

   

 }

ii. public Test(String m){

     

  }

iii. public Test(int a, String b){

 

}

<em>The following should be noted;</em>

In the case of combination (i) and (ii), the constructors have the same number of parameters but different type of parameter. In other words, they both have 1 parameter but while the first one has a parameter type of <em>int</em>, the second has a parameter type of <em>String</em>.

In the case of combination (ii) and (iii), the constructors have different number of parameters and of course different type of parameters. In other words, the second constructor has 1 parameter of type <em>String</em> while the third constructor has 2 parameters of types <em>int</em> and <em>String</em>.

5 0
3 years ago
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