Well, the first one is 2/40=1/20. The 2nd one is 1/39. You multiply these to get 1/780.
The Twenty-Ninth term is -34. The arithmetic sequence is degrading by -2. Below is the sequence.
22, 20, 18, 16, 14, 12, 10, 8, 6, 4, 2, 0, -2, -4, -6, -8, -10, -12, -14, -16, -18, -20, -22, -24, -26, -28, -30, -32, -34
1. First, you must find the constant of variation (k). The problem indicates that t<span>he base of each triangle varies inversely with the height. So, this can be represented as below:
</span>
B=k/H
B is the base of the triangle (B=10).
H is the height of the triangle (H=6).
k is the constant of variation.
2. When you clear "k", you obtain:
B=k/H
k=BxH
k=10x6
k=60
3. Now, you have:
B=60/H
4. You can give any value to "H" and you will obtain the base of the second triangle.
5. If H=12, then:
B=60/H
B=60/12
B=5
6. Therefore, <span>the possible base and height of a second triangle is:
</span>
B=5
H=12
Answer:
The probability that an athlete chosen is either a football player or a basketball player is 56%.
Step-by-step explanation:
Let the athletes which are Football player be 'A'
Let the athletes which are Basket ball player be 'B'
Given:
Football players (A) = 13%
Basketball players (B) = 52%
Both football and basket ball players = 9%
We need to find probability that an athlete chosen is either a football player or a basketball player.
Solution:
The probability that athlete is a football player = 
The probability that athlete is a basketball player = 
The probability that athlete is both basket ball player and football player = 
We have to find the probability that an athlete chosen is either a football player or a basketball player
.
Now we know that;

Hence The probability that an athlete chosen is either a football player or a basketball player is 56%.