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3 years ago

How much mquarts are in 7 liters

Mathematics

2 answers:

GrogVix [38]3 years ago

8 0

Answer:

7.397 us liquid quality

IrinaK [193]3 years ago

7 0

Answer:

the answer is 7.397 if im correct

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Forty tickets are sold for a raffle with two prizes. You buy two tickets. What is the probability that you will win both prizes?

Rina8888 [55]

Well, the first one is 2/40=1/20. The 2nd one is 1/39. You multiply these to get 1/780.

6 0

4 years ago

Find the twenty-ninthninth term of the arithmetic sequence 22, 20, 18, ...

soldi70 [24.7K]

The Twenty-Ninth term is -34. The arithmetic sequence is degrading by -2. Below is the sequence.

22, 20, 18, 16, 14, 12, 10, 8, 6, 4, 2, 0, -2, -4, -6, -8, -10, -12, -14, -16, -18, -20, -22, -24, -26, -28, -30, -32, -34

3 0

3 years ago

Shirley is drawing triangles that have the same area. The base of each triangle varies inversely with the height. What are the p

Romashka-Z-Leto [24]

1. First, you must find the constant of variation (k). The problem indicates that t<span>he base of each triangle varies inversely with the height. So, this can be represented as below:
</span>
B=k/H

B is the base of the triangle (B=10).
H is the height of the triangle (H=6).
k is the constant of variation.

2. When you clear "k", you obtain:

B=k/H
k=BxH
k=10x6
k=60

3. Now, you have:

B=60/H

4. You can give any value to "H" and you will obtain the base of the second triangle.

5. If H=12, then:

B=60/H
B=60/12
B=5

6. Therefore, <span>the possible base and height of a second triangle is:
</span>
B=5
H=12

5 0

3 years ago

I need helpI need helpI need helpI need helpI need helpI need helpI need helpI need help

Y_Kistochka [10]

Answer:

Step-by-step explanation:

3 0

4 years ago

Read 2 more answers

A survey of athletes at a high school is conducted, and the following facts are discovered: 13% of the athletes are football pla

nekit [7.7K]

Answer:

The probability that an athlete chosen is either a football player or a basketball player is 56%.

Step-by-step explanation:

Let the athletes which are Football player be 'A'

Let the athletes which are Basket ball player be 'B'

Given:

Football players (A) = 13%

Basketball players (B) = 52%

Both football and basket ball players = 9%

We need to find probability that an athlete chosen is either a football player or a basketball player.

Solution:

The probability that athlete is a football player = $P(A)= \frac{13}{100}=0.13$

The probability that athlete is a basketball player = $P(B)= \frac{52}{100}=0.52$

The probability that athlete is both basket ball player and football player = $P(A\cap B) = \frac{9}{100}=0.09$

We have to find the probability that an athlete chosen is either a football player or a basketball player $P(A\cup B)$ .

Now we know that;

$P(A\cup B)= P(A) + P(B) - P(A \cap B)\\\\P(A\cup B) = 0.13+0.52-0.09=0.56\\\\P(A\cup B) = \frac{0.56}{100}=56\%$

Hence The probability that an athlete chosen is either a football player or a basketball player is 56%.

5 0

4 years ago