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aksik [14]
3 years ago
12

What is the sum of 8 and 7, doubled

Mathematics
2 answers:
lions [1.4K]3 years ago
7 0
(8+7) x 2

= 15 x 2

= 30
Mandarinka [93]3 years ago
5 0

8+7*2=15+15=30

 so your answer is 30


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Mind my hand writing but I’m not sure what sign to put the “-“ or the “+” ?
Ierofanga [76]

hello!

so the answer that you put there is actually wrong and i'll tell you why and how to do it

so since you are adding the two:

-8x + 9x = x (so you got this part right)

-12 + 4 = -8 (this is where you got it wrong, -12 added 4 goes up in value to -8)

so the final answer is x - 8

i hope this helped and have a nice day!

4 0
3 years ago
Read 2 more answers
given the functions f(x)=4x^2-1, g(x)=x^2-8x+5, and h(x)=-3x^2-12x +1, rank them from least to greatest based on their axis of s
Lesechka [4]
The formula for axis of symmetry is -b/2a.

For f(x):
0/2(4)
0/8
Axis of symmetry= 0

For g(x)
-(-8)/2(1)
8/2
Axis of symmetry= 4

For h(x)
-(-12)/2(-3)
12/-6
Axis of symmetry= -2

Order from least to greatest: -2, 0, 4

Final answer: h(x), f(x), g(x)
7 0
3 years ago
10 to 7 power equals
Korolek [52]

Answer: 10,000,000

Step-by-step explanation: when anything rasied to the power you take what ever the Exponaten is and take how everything was there for example 10⁷ 10x10x10x10x10x10x10. And you multiply that.

6 0
3 years ago
Read 2 more answers
Express 1/10 cm as a fraction of 3 metres​
Liula [17]

Answer:

1/3000

Step-by-step explanation:

3 meters to centimeters:

3 × 100 = 300

= 1/10 ÷ 300

= 1/10/300

= 1/(10×300)

= 1/3000

7 0
3 years ago
Given a standard deck of 52 cards, 3 cards are dealt without replacement. Using this situation, answer the questions below.<b
kherson [118]
Given that <span>3 cards are dealt without replacement in a </span><span>standard deck of 52 cards.

Part A:

There are 4 queens in a standard deck of 52 card, thus the probability that the first card is a queen is given by 4 / 52 = 1 / 13.

Since, the first card is not replaced, thus there are 3 queens remaining and 51 ards remaining in total, thus the probability that the second card is a queen is given</span> by 3 / 51 = 1 / 17

Similarly the probability that the third card is a queen is given by 2 / 50 = 1 / 25.

Therefore, the probability that <span>all three cards are queens is given by

\frac{1}{13} \times \frac{1}{17} \times \frac{1}{25} = \frac{1}{5525}



Part B:

Yes the probability of drawing a queen of heart is independent of the probability of drawing a queen of diamonds because they are separate cards and drawing one of the cards does not in any way affect the chance of drawing the other card.



Part C:

Given that the first card is a queen, then there are 3 queens remaining out of 51 cards remaining, thus the number of cards that are not queen is 51 - 3 = 48 cards.

Therefore, </span>if the first card is a queen, the probability that the second card will not be a queen is given by 48 / 51 = 16 / 17



Part D:

<span>Given that the first two card are queens, then there are 2 queens remaining out of 50 cards remaining.

Therefore, </span>if two of the three cards are queens ,<span>the probability that you will be dealt three queens</span> is given by 2 / 50 = 1 / 25 = 0.04



Part E:

<span>Given that the first two card are queens, then there are 2 queens remaining out of 50 cards remaining, thus the number of cards that are not queen is 50 - 2 = 48 cards.

Therefore, </span>if two of the three cards are queens ,the probability that the other card is not a queen is given by 48 / 50 = 24 / 25 = 0.96
8 0
3 years ago
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