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astraxan [27]
3 years ago
6

QUESTION 3 Find the interest. Round to the nearest cent. $1850 at 8% for 14 months

Mathematics
1 answer:
Genrish500 [490]3 years ago
3 0

Answer:

I=\$172.67

Step-by-step explanation:

we know that

The simple interest formula is equal to

I=P(rt)

where

I is the Interest Value

P is the Principal amount of money to be invested

r is the rate of interest  

t is Number of Time Periods

in this problem we have

t=14/12\ years\\ P=\$1,850\\r=0.08

substitute in the formula above

I=1,850(0.08(14/12))

I=\$172.67

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hope this helped :)
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3 years ago
1. How can you tell that a point on the graph is a maximum or minimum?
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Answer:

1) To see whether it is a maximum or a minimum, in this case we can simply look at the graph. f(x) is a parabola, and we can see that the turning point is a minimum. By finding the value of x where the derivative is 0, then, we have discovered that the vertex of the parabola is at (3, −4).

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3 years ago
The U.S. and many other countries have recently tightened airport security. A sociologist is interested in estimating the propor
melisa1 [442]

Answer:

0.0073 < 0.05, which means that we reject the null hypothesis and conclude that the true proportion of interest is higher than 0.7.

Step-by-step explanation:

Conduct a test to determine whether the true proportion of interest is higher than 0.7.

This means that the null hypothesis is: H_{0}: p = 0.7

And the alternate hypothesis is: H_{a}: p > 0.7

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

0.7 is tested at the null hypothesis:

This means that \mu = 0.7, \sigma = \sqrt{0.7*0.3}

The sociologist found that 375 of the 500 travelers randomly selected and interviewed indicated that the airports were safe.

This means that n = 500, X = \frac{375}{500} = 0.75

Value of the z-statistic:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{0.75 - 0.7}{\frac{\sqrt{0.7*0.3}}{\sqrt{350}}}

z = 2.44

P-value of the test:

Probability of z being larger than 2.44, that is, a proportion larger than 0.75.

This is, looking at the z-table, 1 subtracted by the pvalue of Z = 2.44. S

Z = 2.44 has a pvalue of 0.9927

1 - 0.9927 = 0.0073

0.0073 < 0.05, which means that we reject the null hypothesis and conclude that the true proportion of interest is higher than 0.7.

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3 years ago
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FR.EE POINTS HAVE A GOOD DAY 100PTS :)
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Answer:

Thank u so much have a good day too

5 0
3 years ago
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