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Anastasy [175]
4 years ago
6

I need help on 17 and 23 pls

Mathematics
1 answer:
ludmilkaskok [199]4 years ago
6 0

                           

                          Question # 17 Solution

Answer:

x_{1}= \frac{mx_{2}-y_{2}+y_{1}}{m}

Step-by-step Explanation:

The given expression

m = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}

And we have to solve for x₁

So,

Lets solve for x₁.

m = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}

Multiply both sides by x₂ - x₁

m(x_{2}-x_{1})= (x_{2}-x_{1})\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

m(x_{2}-x_{1})= (y_{2}-y_{1})

mx_{2}-mx_{1}= (y_{2}-y_{1})

-mx_{1}= y_{2}-y_{1}-mx_{2}

Divide both sides by -m

\frac{-mx_{1}}{-m}= \frac{y_{2}-y_{1}-mx_{2}}{-m}

x_{1}= \frac{mx_{2}-y_{2}+y_{1}}{m}

Therefore, x_{1}= \frac{mx_{2}-y_{2}+y_{1}}{m}

                                     Question # 23 Solution

Answer:

n= \frac{bx}{-b + x}

Step-by-step Explanation:

The given expression

\frac{nx}{b}-x=x

And we have to solve for n

So,

Let's solve for n.

\frac{nx}{b}-x=x

Multiply both sides by b.

-bn + nx = bx

Factor out n.

n(-b + x)= bx

Divide both sides by -b + x.

\frac{n(-b + x)}{-b + x}= \frac{bx}{-b + x}

n= \frac{bx}{-b + x}

Therefore, n= \frac{bx}{-b + x}

<em>Keywords: solution, equation</em>

<em>Learn more about the solution of equations from brainly.com/question/12864981</em>

<em>#learnwithBrainly</em>

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