Answer:
15mm
Step-by-step explanation:
we are looking for extension
To get Extension you need the original length and the strain both of which you are given
initial length L = 1.00m
the area A = 0.5mm² = 0.5 mm² = 0.5 x 10⁻⁶ m² ( we are changing to metres squared)
E = 2.0 x 10¹¹ n/m², Young's modulus
P = 1500N, the applied tension
Now to Calculate the stress.
σ = P/A (force/area) = (1500 N)/(0.5 x 10⁻⁶ m²) = 3 x 10⁹ N/m²
Also, Let β = the stretch of the string.
Then the strain is
ε = β/L (extension/ original length)
By definition, the strain is ε = σ/E = (3 x 10⁹ N/m²)/(2 x 10¹¹ N/m²) = 0.015
Therefore β/(1 m) = 0.015β = 0.015 m = 15 mm
Answer: 15 mm
Answer:
x=3
Step-by-step explanation:
all work is shown and pictured
It looks like your equations are
7M - 2t = -30
5t - 12M = 115
<u>Solving by substitution</u>
Solve either equation for one variable. For example,
7M - 2t = -30 ⇒ t = (7M + 30)/2
Substitute this into the other equation and solve for M.
5 × (7M + 30)/2 - 12M = 115
5 (7M + 30) - 24M = 230
35M + 150 - 24M = 230
11M = 80
M = 80/11
Now solve for t.
t = (7 × (80/11) + 30)/2
t = (560/11 + 30)/2
t = (890/11)/2
t = 445/11
<u>Solving by elimination</u>
Multiply both equations by an appropriate factor to make the coefficients of one of the variables sum to zero. For example,
7M - 2t = -30 ⇒ -10t + 35M = -150 … (multiply by 5)
5t - 12M = 115 ⇒ 10t - 24M = 230 … (multiply by 2)
Now combining the equations eliminates the t terms, and
(-10t + 35M) + (10t - 24M) = -150 + 230
11M = 80
M = 80/11
It follows that
7 × (80/11) - 2t = -30
560/11 - 2t = -30
2t = 890/11
t = 445/11
Answer:
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