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3 years ago

∆ABC is reflected about the line y = -x to give ∆A'B'C' with vertices

1 answer:

4 0

Since A‘(-1,1) is on the line y=-x, reflecting it about the line doesn't change its coordinate, so A's coordinate is (-1,1). Reflecting B'(-2,1) about y=-x switches both the sign and the number of x and y, so B=(-1,2), and C'(-1,0) becomes C(0,1). Drawing out the graph with the points and the line helps.

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there are 900 books in the fiction section of the lubrary . which expression has the same value as 900 a. 2x90 b. 10x9 c. 10x90

myrzilka [38]

Answer:

c.10x90

Step-by-step explanation:

if you multiply 10 by 90 it will give you 900. i learned math a weird way. i think this only works with 10's. if you take 1 and 9 and multiply them you will get 9. then there are two zeros in total out of 10 and 90 then you add them to the 9 to get 900

7 0

3 years ago

Read 2 more answers

The surface area, A, of a cylinder is given by the formula A = 2 Trh + 2nr, where ris the radius and h is the height

lord [1]

Answer:

Area = 87.9646 sq. units from A = 28*π sq. units.

However I cannot see this in your answer list, since the numbers look all jumbled. Choice A. looks close to it, since there is a 28...

Step-by-step explanation:

We have a cylinder with height h = 5

radius = 2

We want the surface area of this cylinder.

A = (circumference)*h + 2*(pi)*r^2

A = ( 4*π)*5 + 2*π*(2^2)

A = 20π + 8π = 28 π square units

A = 87.9646 sq.. units

7 0

3 years ago

A boat travels 45 miles upstream (against the current) in 5 hours. The boat travels the same distance downstream in 3 hours. Wha

Leona [35]

R=rate of boat in still water
c=rate of current
d=rt
since you're given that the time it takes to travel the same distance downstream and upstream, your equation will be d_1=d_2, or rt=rt
the rate upstream is r-c and the rate downstream is r+c (because the boat's and river's rates add up)
since you know t_1 and t_1 are 5 and 3, you can now set up 2 equations
5*(r-c)=45 because (time upstream)*(rate upstream)=distance=45 miles
r-c=45/5=9
3*(r+c)=45
r+c=45/3=15
r-c=9 and r+c=15, so r=12 mi/h and c=3 mi/h
If you have any questions please ask

3 0

3 years ago

Can someone please help I tried to attempt it but it wasn’t working for me

kakasveta [241]

b. It depends on the value you assume for the power line voltage. If you assume it is 120 volts, then the ratio to battery voltage is

... (120 volts)/(1.2 volts) = 100

Power line voltage is 100 times as large as battery voltage.

_____

Please be aware of some difficulties in this question.

1. Power line voltage, even if it is "120 volts" varies over time from -170 V to +170 V, so is not really comparable to a battery's voltage, which is steady at 1.2 V.

2. The terminology "times larger" is ambiguous. When we answer the question, "how much larger is a than b," we give the response in terms of the difference a-b. Thus, if a is 2 times larger than b, we might be talking about the difference being twice the value of b. It is preferable to say "times as large as."

5 0

3 years ago

Consider the curve y=x2+3x+5. (a) Find the slope of the secant line to the curve through the points P=(4,33) and Q=(4+h,(4+h)2+3

lawyer [7]

Answer:

a) The slope of the secant line is 11 + h

b) The slope of the curve at P is 11

c) The equation of the tangent line at P is y = 11x - 11

Step-by-step explanation:

y=x²+3x+5

(a) Find the slope of the secant line to the curve through the points P=(4,33) and Q=(4+h,(4+h)²+3(4+h)+5)

(4+h)²+3(4+h)+5 = 16 + 8h + h² + 12 + 3h + 5 = 33 + 11h + h²

slope (m) = yq - yp/xq - xp → m = 33 + 11h + h² - 33/4 + h - 4

m = 11h + h²/h = h(11+h)/h = 11 + h

The slope of the secant line is 11 + h

(b) Use your answer from part (a) to find the slope of the curve at the point P.

As P (4,33) = (4+0, 33+0) at P h is 0, so the slope at P is 11 + 0 = 11

The slope of the curve at P is 11

y - yp = m(x - xp) → y - 33 = 11(x - 4) → y - 33 = 11x - 44 → y = 11x - 11

The equation of the tangent line at P is y = 11x - 11

3 0

3 years ago