The discriminante :
b^2-4ac
1^2 - 4 * -2 * -28 = 1 - 224 = -223
When the discriminant (b^2-4ac) is less than 0, the equation had no real solutions.
-223<0, so, 2x^2+x-28 = 0 has no real solutions.
Hope that helps :)
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Answer:
Jace~
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((-4)^5)^8 / ((-4)^7)^3
= (-4)^40 / (-4)^21
= (-4)^20
Answer:
3rd option
Step-by-step explanation:
(
)(x)
= 
=
← factorise numerator and denominator
=
← cancel (2x + 1) on numerator/ denominator
= 