Question

If the length of the side of a square is doubled, what is the ratio of the areas of the original square to the area of the new square?

Answer 1

Answer:

$\frac{1}{4}$

Step-by-step explanation:

Let 's' be the side of the original square

the length of the side of a square is doubled, so the length of the new square is 2s

Area of the original square with side length 's' is $s^2$

Area of the new square with side length '2s' is $(2s)^2=4s^2$

Area of the new square is 4  times the area of the original square

ratio of the areas of the original square to the area of the new square

$\frac{s^2}{4s^2} =\frac{1}{4}$