A company is considering producing some new products. Based on past records, management believes that there is a 70% chance that
1 answer:
The probability that the results indicate an unsuccessful market for the product and the product is actually unsuccessful is P=0.77.
<h3>What is probability?</h3>Probability is defined as the ratio of the number of favourable outcomes to the total number of outcomes in other words the probability is the number that shows the happening of the event.
Events:
S: success
F: failure
MS: market research forecast a success
MF: market research forecast a failure
The information we have is:
P(S)=0.70
P(F)=0.30
P(S|MS)=0.90
P(F|MS)=0.20
If P(F|MS)=0.20, we can derive that P(F|MF)=0.80. That is, the failed products were predicted to be a failure based on market research 80 per cent of the time.
We also can conclude that P(S|MF)=0.10.
We can calculate the probability of having a forecast of a failure, given that the product is actually unsuccessful as:
The probability that the results indicate an unsuccessful market for the product and the product is actually unsuccessful is P=0.77.
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Answer:
see attached
Step-by-step explanation:
For x < -6, the function has a slope of -1 and an x-intercept of -6.
For x > -6, the function has a slope of 2 and an x-intercept of -6.
The function given here is not defined at x=6, so there is a hole at (-6, 0).
Answer:
2/5
Step-by-step explanation:
Hi! Whenever you find a limit, you first directly substitute x = 5 in.
Hm, looks like we got 0/0 after directly substitution. 0/0 is one of indeterminate form so we have to use another method to evaluate the limit since direct substitution does not work.
For a polynomial or fractional function, to evaluate a limit with another method if direct substitution does not work, you can do by using factorization method. Simply factor the expression of both denominator and numerator then cancel the same expression.
From x²-6x+5, you can factor as (x-5)(x-1) because -5-1 = -6 which is middle term and (-5)(-1) = 5 which is the last term.
From x²-25, you can factor as (x+5)(x-5) via differences of two squares.
After factoring the expressions, we get a new Limit.
We can cancel x-5.
Then directly substitute x = 5 in.
Therefore, the limit value is 2/5.
L’Hopital Method
I wouldn’t recommend using this method since it’s <em>too easy</em> but only if you know the differentiation. You can use this method with a limit that’s evaluated to indeterminate form. Most people use this method when the limit method is too long or hard such as Trigonometric limits or Transcendental function limits.
The method is basically to differentiate both denominator and numerator, do not confuse this with quotient rules.
So from the given function:
Differentiate numerator and denominator, apply power rules.
<u>Differential</u> (Power Rules)
<u>Differentiation</u> (Property of Addition/Subtraction)
Hence from the expressions,
<u>Differential</u> (Constant)
Therefore,
Now we can substitute x = 5 in.
Thus, the limit value is 2/5 same as the first method.
Notes:
- If you still get an indeterminate form 0/0 as example after using l’hopital rules, you have to differentiate until you don’t get indeterminate form.