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torisob [31]
3 years ago
15

Please help on picture !!!

Mathematics
1 answer:
kicyunya [14]3 years ago
3 0

Answer:

its 14, but not rounded its 14.28

Step-by-step explanation:

34/100. multiply 34 and 42, then divide by 100

hope this helps :)

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The population of mosquitoes in a certain area increases at a rate proportional to the current population, and in the absence of
Alexandra [31]

Answer:

Population of mosquitoes in the area at any time t is:

P(t) =504,943.26  -104,943.26e^{0.693t}

Step-by-step explanation:

assume population at any time t = P(t)

population increases at a rate proportional to the current population:

⇒dP/dt ∝ P

 \implies \frac{dP}{dt} =kP----(1)

where k is constant rate at which population is doubled

solving (1)

ln|P(t)|=kt +C\\P(t)= e^{kt+C}\\P(t)=Ce^{kt}

t=0\\P(0) = P_{o}\\\implies C= P_{o}\\P(t) =P_{o}e^{kt}\\ ---- (2)

initial population = 400,000

population is doubled every week

                                                 ⇒P(1)=2P(0)

Using (2)

                                 P_{o}e^{k(1)} = 2P_{o} e^{k(0)}\\

                                            e^{k} =2\\k=ln|2|\\

In presence of predators amount is decreased by 50,000 per day

Then amount decreased per week = 350,000

In this case (1) becomes

\frac{dP}{dt}=kP-350,000\\\frac{dP}{dt} - kP=-350,000\\ ---(3)

solving (3) by calculating integrating factor

                                          I.F=e^{\int-k dt}

Multiplying I.F with all terms of (3)

e^{-kt}\frac{dP}{dt} - ke^{-kt}P =-350,000 e^{-kt}\\\frac{d}{dt}(e^{-kt}P) =  -350,000 e^{-kt}

Integrating w.r.to t

                         e^{-kt}P(t)= \frac{350,000e^{-kt}}{k} +C

                         P(t) =\frac{350,000}{k} +Ce^{kt}\\

                                          k=ln|2| =0.693

                          P(t) =504,943.26 + Ce^{0.693t}\\

at t=0

                        P(0) =504,943.26 + Ce^{0.693(0)}

                        400,000 =504,943.26 + C

                           C = -104,943.26

So, population of mosquitoes in the area at any time t is

                  P(t) =504,943.26  -104,943.26e^{0.693t}

6 0
3 years ago
Damerly Company (a Utah employer) wants to give a holiday bonus check of $250 to each employee. Since it wants the check amount
Marat540 [252]

Answer:

Withholding taxes

Federal income tax withheld= $100.24

OASDI tax withheld=$24.86

HI tax withheld=$5.81

Utah income tax withheld=$20.05

Gross amount= $400.96

Step-by-step explanation:

Amount per employee(desired net pay)= $250.00

Federal rate=25%=0.25

OASDI tax=6.2%=0.062

HI tax witheld= 1.45%=0.0145

Utah income tax=5%=0.05

Combined taxes= 0.25+0.062+0.0145+0.05=0.3765

Gross pay=Desired net pay/(1-all taxes)

Gross pay= 250/(1-0.3765)=250/0.6235=400.96

Working backwards

Since we have gross bonus of $400.96

Federal income tax withheld is 0.25of$400.96= $100.24

OASDI tax is 0.062of$400.96=$24.86

HI tax is 0.0145of$400.96=$5.81

Utah income tax is 0.05of$400.96=$20.05

Total deductions=$100.24+$24.86+$5.81+$20.05= $150.96

Net income is $400.96-$150.96= $250.00

6 0
3 years ago
Please help, you can just slide the answer
nikdorinn [45]

Answer:

c is correct have a nice day

Step-by-step explanation:

3 0
3 years ago
Write an equation of the line that passes through (-4,-1) and is perpendicular to the line y =4/3x+6
uysha [10]
The slope would be the negative reciprocal = -3/4
plug in (-4,-1) for x and y to find b.
y = mx+b
-1 = (-3/4)(-4) + b
-1 = 3 + b
-4 = b

THE ANSWER
y = -3/4x -4
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Britany wants to read a book. In her room, she has 5 mysteries, 15 historical fictions, 12 modern fantasies, and 7 blographies.
Leno4ka [110]

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