Answer:
And the best option would be:
c. 1450 +/- 12
Step-by-step explanation:
Information provided
represent the sample mean for the SAT scores
population mean (variable of interest)
represent the sample variance given
n=25 represent the sample size
Solution
The confidence interval for the true mean is given by :
(1)
The sample deviation would be 
The degrees of freedom are given by:
The Confidence is 0.954 or 95.4%, the value of 
and 
, assuming that we can use the normal distribution in order to find the quantile the critical value would be 
The confidence interval would be
And the best option would be:
c. 1450 +/- 12
Answer:
10
Step-by-step explanation:
say x=0
then y would be 1
increasing x by 5 makes x=5
and then 5 x 2 + 1=11
so y went from 1-11(difference of 10) with the variation
so the answer is 10
Answer: -56 -17 0 5 34
Step-by-step explanation:
The more left you go on a number line the smaller it is
It’s not b or d so it’s either a or c. Hope this helped
