ANSWER:
(y^2+1)+1=3
Hope it helps u! :)
25 has 3 factors: 1, 5 and 25. Only those 3 numbers can be evenly divided into 25. 1 is a factor for every number, 5 can be divided into 25, 5 times and a number is always a factor of itself as well.
Answer: 4.27% of adults in the USA have stage 2 high blood pressure.
Step-by-step explanation:
Let x be a random variable that denotes a person with high blood pressure .
Given: Average blood pressure: 
Standard deviation: 
Someone qualifies as having Stage 2 high blood pressure if their systolic blood pressure is 160 or higher.
The probability that an adult in the USA have stage 2 high blood pressure:
![P(x\geq160)=P(\dfrac{x-\mu}{\sigma}}\geq\dfrac{160-122}{22})\\\\=P(z\geq1.72)\ \ \ [z=\dfrac{x-\mu}{\sigma}]\\\\=1-P(z](https://tex.z-dn.net/?f=P%28x%5Cgeq160%29%3DP%28%5Cdfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D%7D%5Cgeq%5Cdfrac%7B160-122%7D%7B22%7D%29%5C%5C%5C%5C%3DP%28z%5Cgeq1.72%29%5C%20%5C%20%5C%20%5Bz%3D%5Cdfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D%5D%5C%5C%5C%5C%3D1-P%28z%3C1.72%29%5C%5C%5C%5C%3D1-0.9573%5C%20%5C%20%5BBy%5C%20p-value%5C%20table%5D%5C%5C%5C%5C%3D0.0427%3D4.27%5C%25)
Hence, 4.27% of adults in the USA have stage 2 high blood pressure.
Answer:
D = L/k
Step-by-step explanation:
Since A represents the amount of litter present in grams per square meter as a function of time in years, the net rate of litter present is
dA/dt = in flow - out flow
Since litter falls at a constant rate of L grams per square meter per year, in flow = L
Since litter decays at a constant proportional rate of k per year, the total amount of litter decay per square meter per year is A × k = Ak = out flow
So,
dA/dt = in flow - out flow
dA/dt = L - Ak
Separating the variables, we have
dA/(L - Ak) = dt
Integrating, we have
∫-kdA/-k(L - Ak) = ∫dt
1/k∫-kdA/(L - Ak) = ∫dt
1/k㏑(L - Ak) = t + C
㏑(L - Ak) = kt + kC
㏑(L - Ak) = kt + C' (C' = kC)
taking exponents of both sides, we have

When t = 0, A(0) = 0 (since the forest floor is initially clear)


So, D = R - A =

when t = 0(at initial time), the initial value of D =
