6 ÷ 3/4 = 6/1 ×4/3 = 24/3= 8... 8 sweet potatoe pies
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5x9= 45 remainder3 which means it 9 3/5
Answer:
this question is missing something
Answer:
![\boxed{ \bold{ \sf{x = 16}}}](https://tex.z-dn.net/?f=%20%5Cboxed%7B%20%5Cbold%7B%20%5Csf%7Bx%20%3D%2016%7D%7D%7D)
![\boxed{ \bold{ \sf{m < AFD = 82}}}](https://tex.z-dn.net/?f=%20%5Cboxed%7B%20%5Cbold%7B%20%5Csf%7Bm%20%3C%20AFD%20%3D%2082%7D%7D%7D)
Step-by-step explanation:
![\sf{5x + 18 = 3x + 50}](https://tex.z-dn.net/?f=%20%5Csf%7B5x%20%2B%2018%20%3D%203x%20%2B%2050%7D)
( Being vertically opposite angles)
Vertically opposite angles are always equal.
Move variable to L.H.S and change it's sign
Similarly, Move constant to R.H.S and change it's sign
⇒![\sf{5x - 3x = 50 - 18}](https://tex.z-dn.net/?f=%20%5Csf%7B5x%20%20-%203x%20%3D%2050%20-%2018%7D)
Collect like terms
⇒![\sf{2x = 50 - 18}](https://tex.z-dn.net/?f=%20%5Csf%7B2x%20%3D%2050%20-%2018%7D)
Subtract 18 from 50
⇒![\sf{2x = 32}](https://tex.z-dn.net/?f=%20%5Csf%7B2x%20%3D%2032%7D)
Divide both sides of the equation by 2
⇒![\sf{ \frac{2x}{2} = \frac{32}{2} }](https://tex.z-dn.net/?f=%20%5Csf%7B%20%5Cfrac%7B2x%7D%7B2%7D%20%20%3D%20%20%5Cfrac%7B32%7D%7B2%7D%20%7D)
Calculate
⇒![\sf{x = 16}](https://tex.z-dn.net/?f=%20%5Csf%7Bx%20%3D%2016%7D)
The value of x is 16
Now, let's find value of m<AFD :
( sum of angle in straight line )
plug the value of x
⇒![\sf{m < AFD + 5 \times 16 + 18 = 180}](https://tex.z-dn.net/?f=%20%5Csf%7Bm%20%3C%20AFD%20%2B%205%20%5Ctimes%2016%20%2B%2018%20%3D%20180%7D)
Multiply the numbers
⇒![\sf{m < AFD + 80 + 18 = 180}](https://tex.z-dn.net/?f=%20%5Csf%7Bm%20%3C%20AFD%20%2B%2080%20%2B%2018%20%3D%20180%7D)
Add the numbers
⇒![\sf{m < AFD + 98 = 180}](https://tex.z-dn.net/?f=%20%5Csf%7Bm%20%3C%20AFD%20%2B%2098%20%3D%20180%7D)
Move constant to R.H.S and change it's sign
⇒![\sf{m < AFD = 180 - 98}](https://tex.z-dn.net/?f=%20%5Csf%7Bm%20%3C%20AFD%20%3D%20180%20-%2098%7D)
Subtract 98 from 180
⇒![\sf{m < AFD = 82}](https://tex.z-dn.net/?f=%20%5Csf%7Bm%20%3C%20AFD%20%3D%2082%7D)
Value of m<AFD = 82
Hope I helped!
Best regards!!
Answer:
14/45
Step-by-step explanation:
So we have the fraction:
![0.3\bar1=0.31111...](https://tex.z-dn.net/?f=0.3%5Cbar1%3D0.31111...)
We can do this algebraically. Follow to following steps:
Let's let this number equal to n. Thus:
![0.31111...=n](https://tex.z-dn.net/?f=0.31111...%3Dn)
Since there is only 1 digit repeating, let's multiply everything by 10. So:
![3.1111...=10n](https://tex.z-dn.net/?f=3.1111...%3D10n)
Now, subtract n from both sides:
![3.1111-n=10n-n](https://tex.z-dn.net/?f=3.1111-n%3D10n-n)
On the left, substitute the number for n. On the right, combine like terms:
![3.1111...-0.31111...=9n](https://tex.z-dn.net/?f=3.1111...-0.31111...%3D9n)
All of the 1s will cancel. So:
![3.1-0.3=9n](https://tex.z-dn.net/?f=3.1-0.3%3D9n)
Subtract:
![2.8=9n](https://tex.z-dn.net/?f=2.8%3D9n)
Divide both sides by 9:
![n=2.8/9](https://tex.z-dn.net/?f=n%3D2.8%2F9)
Remove the decimal by multiplying both sides by 10:
![n=28/90](https://tex.z-dn.net/?f=n%3D28%2F90)
Reduce:
![n=14/45](https://tex.z-dn.net/?f=n%3D14%2F45)
And we're done!
Use a calculator to check:
![14/45\stackrel{\checkmark}{=}0.31111...](https://tex.z-dn.net/?f=14%2F45%5Cstackrel%7B%5Ccheckmark%7D%7B%3D%7D0.31111...)