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Tanya [424]
3 years ago
12

How much time is it from 8:00 am to 11:25 am?

Mathematics
2 answers:
Trava [24]3 years ago
8 0

Answer: 3 hours 25 mins.

elena55 [62]3 years ago
4 0

Answer:

give this man brainiest

Step-by-step explanation:

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Please answer asap thanks
Bad White [126]

Answer:

7y - 28

Step-by-step explanation:

if you multply 7 with inside parenthesis you will get 7y - 28.

4 0
3 years ago
Х<br> -3<br> 3 so<br> Plz explain this its a fraction
alexandr1967 [171]

Answer:

x = 9

Step-by-step explanation:

x−(3)(3=x+−9 )

8 0
3 years ago
Please this is my last problem and all my points just solve this for im begging
zheka24 [161]

Answer:

72.54

Step-by-step explanation:

Use formula for trapezoid: a+b/2 * h

5 0
3 years ago
Read 2 more answers
An automobile company wants to determine the average amount of time it takes a machine to assemble a car. A sample of 40 times y
aksik [14]

Answer:

A 98% confidence interval for the mean assembly time is [21.34, 26.49] .

Step-by-step explanation:

We are given that a sample of 40 times yielded an average time of 23.92 minutes, with a sample standard deviation of 6.72 minutes.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

                               P.Q. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample average time = 23.92 minutes

             s = sample standard deviation = 6.72 minutes

             n = sample of times = 40

             \mu = population mean assembly time

<em> Here for constructing a 98% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation. </em>

<u>So, a 98% confidence interval for the population mean, </u>\mu<u> is; </u>

P(-2.426 < t_3_9 < 2.426) = 0.98  {As the critical value of z at 1%  level

                                               of significance are -2.426 & 2.426}  

P(-2.426 < \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } } < 2.426) = 0.98

P( -2.426 \times {\frac{s}{\sqrt{n} } } < {\bar X-\mu} < 2.426 \times {\frac{s}{\sqrt{n} } } ) = 0.98

P( \bar X-2.426 \times {\frac{s}{\sqrt{n} } } < \mu < \bar X+2.426 \times {\frac{s}{\sqrt{n} } } ) = 0.98

<u>98% confidence interval for</u> \mu = [ \bar X-2.426 \times {\frac{s}{\sqrt{n} } } , \bar X+2.426 \times {\frac{s}{\sqrt{n} } } ]

                                     = [ 23.92-2.426 \times {\frac{6.72}{\sqrt{40} } } , 23.92+2.426 \times {\frac{6.72}{\sqrt{40} } } ]  

                                    = [21.34, 26.49]

Therefore, a 98% confidence interval for the mean assembly time is [21.34, 26.49] .

7 0
3 years ago
Solve V=1/3bh for h. (1/3 is a fraction, idk if that matters.)
Vadim26 [7]

Answer:

3V/b = h

Step-by-step explanation:

Step 1: Write equation

V = 1/3bh

Step 2: Multiply both sides by 3

3V = bh

Step 3: Divide both sides by b

3V/b = h

8 0
3 years ago
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