Using the given information, we can say the following:
Width (W) = x
Length (L) = (2x - 4)
Area of Rectangle = L × W
Using this, we can formulate an equation for rectangle in question:
x(2x - 4) = 30
Expand and move everything to one side:
2x² - 4x - 30 = 0
Simplify by dividing everything on both sides by 2:
x² - 2x - 15 = 0
Factorise:
(x + 5)(x - 3) = 0
Set each factor equal to 0 and solve for x:
x + 5 = 0
x = -5 (a dimension cannot be negative so this is not the solution we want)
x - 3 = 0
x = 3 (this is the solution)
x = W = 3"
L = 2x - 4
L = 2(3) - 4
L = 2"
So, the length the rectangle is 2" and the width is 3"
Answer:
b. y=sec(x/3) and y=-1
Step-by-step explanation:
sec(x/3) + 4 > 2 − sec(x/3)
2 sec(x/3) > -2
sec(x/3) > -1
Graph y = sec(x/3) and y = -1.
<span>In order for you to be able to solve this problem you have to first identify what the questions is asking. In this case it wants to know the approximation of what the semiannual income that Sarah will be able to draw.
To solve this you simply have to find the future value of her investment prior to retirement and use the as her investment amount upon retirement.
<span>I hope it helps, Regards. </span></span>
Let u = 5x+1. Then du = 5·dx, and your integral is
Factors of 21 are : 1,3,7,21....yes, this is correct...true
