write a paragraph describing three senses that circus entertainers rely on explain why it is important

1 answer:

7 0

I'm glad you asked because I just watched a video about all the senses(not just five), so hope this helps. :)

Circus Performers rely on many different senses, but here are the most important ones.

There are way more than five senses and a lot of people don't know that.
One of the senses they use is equilibrioception. It may sound very brainy, but it's just a big word for balance. Some tightrope walkers use this.

Another sense they use is touch. This is common. All circus performers use this to perform and make their crowd laugh!

The last sense is Magnetoception. Another big word with small meaning. This word just means they know the direction they're going to perform.

Circus Performers rely on many different senses, but the most important ones have been stated.

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The equilateral triangular cross sections of a solid with base an arch of y = sin(x) on

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We can define the base of each equilateral section as $b(x) = \sin(x)$ since this is the distance from the x-axis to the function $y=\sin(x)$ .

An equilateral triangle's area can have a function defined solely by the base. Since all sides are equal, the height of the triangle can be found via pythagorean theorem as: $A(b)=\frac{1}{2}b\sqrt{b^2+\left (\frac{b}{2} \right)^2} = \frac{b}{2}\sqrt{\frac{5b^2}{4}}$

But we know that the base $b(x)$ is a function of x. We also can then state that Area $A(b(x))$ is also a function of x. Specifically: $A(x) = \frac{\sin(x)}{2}\sqrt{\frac{5\sin^2(x)}{4}}$ .

Then if we integrate the area function A(x) from 0 to pi, we get the total volume:

$\displaystyle \int_0^{\pi} A(x) dx = \int_0^{\pi} \frac{\sin(x)}{2}\sqrt{\frac{5\sin^2(x)}{4}} dx = \int_0^{\pi} \frac{\sqrt{5} \sin^2(x)}{4}dx$