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riadik2000 [5.3K]
3 years ago
5

Hay que envasar 3582 botellas, en donde en cada caja entran 24 botellas. Que

Mathematics
1 answer:
Mariana [72]3 years ago
3 0

Answer:

La operación es de división:

C=3582/24=149.25

Se envasan 149 cajas y quedan 6 botellas para la próxima caja.

The operation is division:

C=3582/24=149.25

149 boxes are completed and 6 bottles are left for the next box.

Step-by-step explanation:

Hay que dividir la cantidad de botellas a envasar (3582) por la cantidad de botellas que entran en cada caja (24).

Esta operación nos da:

C=3582/24=149.25

Podremos llenar 149 cajas por completo, pero nos sobra el contenido de 0.25 cajas, que equivale a 0.25*24=6 botellas.

You have to divide the total amount of bottles (3582) by the amount of bottles per box (24).

Then you have the operation:

C=3582/24=149.25

We can fill 149 complete boxes, but we are left with 0.25 boxes, which is equivalent to 0.25*24=6 bottles.

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WITCHER [35]

Answer:

C. 2/12

Step-by-step explanation:

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6 0
2 years ago
Mrs. Kato has 6 bags of dried beans and a 2-pound bag of rice in one shopping bag. In another shopping bag she has a 5-pound bag
Serjik [45]

Given:

Mrs. Kato has 6 bags of dried beans and a 2-pound bag of rice in one shopping bag.

In another shopping bag she has a 5-pound bag of flour.

The two shopping bags weigh the same amount.

To find:

The weight of each bag of dried beans.

Solution:

Let x be the weight of each bag of dried beans.

So, weight of 6 bags of dried beans = 6x.

According to the question,

Weight of first bag = (6x + 2) pounds

Weight of second bag = 5 pounds

The two shopping bags weigh the same amount. So,

6x+2=5

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Divide both sides by 6.

x=\dfrac{3}{6}

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Therefore, the weight of each bag of dried beans is 0.5 pounds.

5 0
3 years ago
Find the HCF and LCM of 4x^2 - 36 ,2x^2 - 12x + 18 and 2x^2 + x - 21​
olga_2 [115]

Answer:

(x-3), 4 (x - 3)^2 (x + 3) (2 x + 7)

Step-by-step explanation:

Factor all the expressions,

1st expression= 4x^2 - 36=4(x^2-9)=4(x+3)(x-3)

2nd expression=2x^2 - 12x + 18 =2(x^2-6x+9)=2 (x - 3)^2=2(x-3)(x-3)

3rd expression=2x^2 + x - 21​=(x - 3) (2 x + 7)

HCF=Commo factor=(x-3)

LCF=Common factor*Remaining factor=4(x+3)(x-3)(x-3) (2 x + 7)=4 (x - 3)^2 (x + 3) (2 x + 7)

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