Answer:
obtuse
Step-by-step explanation:
hope it helps. :)
30 ounces of water for 5 teaspoons of lemon
Answer:
-sqrt(3) -i = 2 cis (7pi/6)
Step-by-step explanation:
-sqrt(3) -i
We can find the radius
r = sqrt( (-sqrt(3)) ^2 + (-1) ^2)
= sqrt( 3 + 1)
= sqrt(4)
= 2
theta = arctan (y/x)
arctan (-1/-sqrt(3))
arctan (1/sqrt(3))
theta = pi/6
But this is in the first quadrant, and we need it in the third quadrant
Add pi to move it to the third quadrant
theta = pi/6 + 6pi/6
=7pi/6
-sqrt(3) -i = 2 cis (7pi/6)
Answer:
1.1
Step-by-step explanation:
In this image, we can see that every box, we add 0.2
From 0.1 to 0.3, we add 0.2
We continue with this pattern for the rest of the boxes
When adding decimals, you can imagine it like you are adding normal numbers, and that you are carrying extra (more than 9) to the next column in the same way.
{column/place value}
At first, it might seem like adding 0.2 to 0.9 would result in 0.11, but let's think that through a little bit more. We know that 0.1 is less than 0.2, so, it doesn't make sense for that to be the sum.
Instead, we have to carry the 11 over to the other side of the decimal. (This is because each place value is equal to 10 of the value to the right. If we add digits in the ones place that add up to 10, we carry the "1" over to the right, into the tens place.)
So, we carry the "1" from 11 to the one's place. Now, we are left with
1.1
(hope this helps!! decimals can be tricky at first)
Answer: Choice B
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A more in depth look
Choice A is true because the points are going downward as you read from left to right. The points aren't all on the same line but they are close to one. We can cross choice A off the list.
Choice B is false. So this is the answer. The fact that the points are close to the same line indicates that the r value is close to -1 rather than 0. If the points were randomly scattered about, or if they fell on a curve such as a parabola, then the linear correlation coefficient r would be (closer to) zero.
Choice C is true. The explanatory variable is the independent variable x. We can cross choice C off the list.
Choice D is true. The points are fairly close to the same straight line. It's not perfect but it's good enough. We can cross choice D off the list.
