Answer:
Shop B
Step-by-step explanation:
Hi there!
To solve this question, we can find the new prices of each oven and identify which one is cheaper.
<u>Shop A</u>
Usual price: $190
Discount: 15%
First, we must subtract the discount percent from 100:
100 - 15 = 85
Therefore, the new price of the product will be 85% of the original price. Find 85% of $190:
190 × 0.85
Therefore, the new price is $161.50.
<u>Shop B</u>
Usual price: $200
Discount: 20%
Again, subtract 20 from 100:
100 - 20 = 80
This means that the new price of the oven is 80% of the original price:
200 × 0.8 = 160
Therefore, the new price is $160.
Because a $160 oven is cheaper than a $161.50 oven, Shop B sells the oven at a lower price.
I hope this helps!
1. Eyeballing the data, the best fit will be pretty close to a line between the leftmost point and the rightmost point.
We estimate those points as (4,220) and (28,470)
The point point form for a line joining (a,b) and (c,d) is
(c-a)(y-b) = (d-b)(x-a)
(28 - 4)(y - 220) = (470 - 220)(x - 4)
24(y - 220) = 250(x-4)
24y - 5280 = 250x - 1000
24y = 250 x + 4280
y = (250/24) x+ (4280/24)
Approximately that's,
y = 10.4 x + 178
Answer: 4th choice, 10.4x + 180
2. For 48 wheelbarrows,
y = 10.4(48)+180 = 679.2
Answer: 679.2 liters of sand
9 games
You can get this by multiplying each percentage by the total number of games to see what they have to expect.
.55*180 = 99 games (red team)
.60*180 = 108 games (blue team)
Now subtract the blue team expectation from the red team.
108 - 99 = 9 games.
The following are the ages of 13 history teachers in a school district. 24, 27, 29, 29, 35, 39, 43, 45, 46, 49, 51, 51, 56 Notic
salantis [7]
Answer:
Below in bold.
Step-by-step explanation:
Minimum 24
Lower quartile 29
Median 43
Upper quartile = (49 + 51) / 2 = 50
Maximum = 56
Interquartile range = 50-29 = 21.
Answer:
We accept the alternate hypothesis and conclude that mean SAT score for Stevens High graduates is not the same as the national average.
Step-by-step explanation:
We are given the following in the question:
Population mean, μ = 510
Sample mean, 
= 502
Sample size, n = 60
Sample standard deviation, s = 30
Alpha, α = 0.05
First, we design the null and the alternate hypothesis
We use Two-tailed t test to perform this hypothesis.
Formula:
Putting all the values, we have
Now,
Since,
We reject the null hypothesis and fail to accept it.
We accept the alternate hypothesis and conclude that mean SAT score for Stevens High graduates is not the same as the national average.
