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Pepsi [2]
3 years ago
13

Simplify 4(6 - 2x) - 3(3 - 4x)

Mathematics
2 answers:
Vadim26 [7]3 years ago
6 0

Answer:

4x + 15

Step-by-step explanation:

4(6-2x) -3(3-4x)

open each brackets with the number in front of em

24 -8x-9+12x

collect like terms

-8x+12x-9+24

4x+15

LiRa [457]3 years ago
5 0

Answer:

-20x+15 is your answer

Step-by-step explanation:

Solve by distributing and combing like terms

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PLEASE HELP!!!!!! ASAP
deff fn [24]

the first one. The camera focuses on the audience


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3 years ago
A farmer owns pigs, chickens, and ducks. When all her animals are together, she has 30 feathered animals, and the animals all to
tatiyna

To solve this problem, let us first assign some variables. Let us say that:

x = pigs

y = chickens

z = ducks

 

From the problem statement, we can formulate the following equations:

1. y + z = 30                                         ---> only chicken and ducks have feathers

2. 4 x + 2 y + 2 z = 120                      ---> pig has 4 feet, while chicken and duck has 2 each

3. 2 x + 2 y + 2 z = 90                        ---> each animal has 2 eyes only

 

Rewriting equation 1 in terms of y:

y = 30 – z

Plugging this in equation 2:

4 x + 2 (30 – z) + 2 z = 120

4 x + 60 – 2z + 2z = 120

4 x = 120 – 60

4 x = 60

x = 15

 

From the given choices, only one choice has 15 pigs. Therefore the answers are:

She has 15 pigs, 12 chickens, and 18 ducks.

3 0
3 years ago
Please answer this mathematical problem.
n200080 [17]

x = total amount of gumballs

let's start subtracting the balls she's giving away

\stackrel{total}{x}-\stackrel{\textit{to jaysen}}{\cfrac{x}{2}}\implies \stackrel{\textit{what's left}}{\cfrac{x}{2}}~\hfill \stackrel{\textit{half of what's left to Marinda}}{\cfrac{~~ \frac{x}{2}~~}{2}\implies \cfrac{x}{4}} \\\\\\ \stackrel{\textit{what was left minus Marinda's}}{\cfrac{x}{2}-\cfrac{x}{4}\implies \stackrel{\textit{what's left}}{\cfrac{x}{4}}}~\hfill ~\hfill \stackrel{\textit{a third of what's left to Zack}}{\cfrac{~~ \frac{x}{4}~~}{3}\implies \cfrac{x}{12}}

\stackrel{\textit{what was left minus Zack's}}{\cfrac{x}{4}-\cfrac{x}{12}\implies \stackrel{\textit{what's left}}{\cfrac{x}{6}}}~\hfill \stackrel{\textit{her sister gets 5 balls of what's left}}{ \cfrac{x}{6}-5 }

and we also know that after all that has been subtracted, she's only left with 5, so we can say that

\stackrel{\textit{what's finally left}}{\cfrac{x}{6}-5}~~ = ~~\stackrel{\textit{what's finally left}}{5}\implies \cfrac{x}{6}=10\implies \boxed{x = 60}

5 0
2 years ago
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natima [27]
No no no no no no non no
7 0
2 years ago
Read 2 more answers
What is the answer for this question
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