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Yuliya22 [10]
3 years ago
14

The question is below​

Mathematics
1 answer:
Cloud [144]3 years ago
3 0

Answer:

See below.

Step-by-step explanation:

a.

The first figure has 1 square. The second figure has a column of 2 squares added to the left. The third figure has a column of 3 squares added to the left. Each new figure has a column of squares added to the left containing the same number of squares as the number of the figure.

b.

Figure 10 has 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 = 55 squares.

c.

The formula for adding n positive integers starting at 1 is:

1 + 2 + 3 + ... + n = n(n + 1)/2

For figure 55, n = 55.

n(n + 1)/2 = 55(56)/2 = 1540

d.

Let's use the formula set equal to 190 and solve for n. If n is an integer, then we can.

n(n + 1)/2 = 190

n(n + 1) = 380

We know that 380 = 19 * 20, so n = 19.

Answer: yes

e.

Use the formula above,

S = n(n + 1)/2, where S is the sum.

f.

n(n + 1) = 1478

38 * 39 = 1482

37 * 38 = 1406

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lakkis [162]

Answer:

Option B.

Step-by-step explanation:

From the given figure it clear that the the vertices of the polynomial are Q(2,0), R(4,5), S(8,7), T(6,4) and U(10,3).

Distance formula:

d=\sqrt{(x-2-x_1)^2+(y_2-y_1)^2}

Using distance formula, we get

QR=\sqrt{\left(4-2\right)^2+\left(5-0\right)^2}=\sqrt{29}

RS=\sqrt{\left(8-4\right)^2+\left(7-5\right)^2}=2\sqrt{5}

ST=\sqrt{\left(6-8\right)^2+\left(4-7\right)^2}=\sqrt{13}

TU=\sqrt{\left(10-6\right)^2+\left(3-4\right)^2}=\sqrt{17}

QU=\sqrt{\left(10-2\right)^2+\left(3-0\right)^2}=\sqrt{73}

Now, the perimeter of the polynomial is

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Therefore, the correct option is B.

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