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musickatia [10]
3 years ago
13

If Dr. I.M. Smart mixes 50ml of a 20% acid in water solution with 30ml of acid, what is the quantity and concentration of the fi

nal solution?
Mathematics
2 answers:
Sergio [31]3 years ago
8 0

Answer:

80ml of the solution with a 50% acid concentration.

Step-by-step explanation:

Amount of acid in the water solution:

50ml * 20%= 10 ml

∴There is 10ml of acid in the solution.

Final amount of liquid:

50ml + 30ml = 80ml

Final amount of Acid:

10ml + 30ml = 40 ml

Concentration of Acid in Solution

40ml / 80ml = 0.5 = 50%

soldier1979 [14.2K]3 years ago
4 0
50 ml * 20% = 10 ml
50+30 =80
10+30 =40
40/80=50%
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58 inches

Step-by-step explanation:

In order to find the perimeter of a shape, you must add up the total length of all the sides. 15 inches + 12 inches + 8 inches + 9 inches + 14 inches = 58 inches.

7 0
3 years ago
Below is the data on the percentage of 25- to 34-year-olds in each of the 50 states and the District of Columbia, listed in alph
NARA [144]

Answer:

Step-by-step explanation:

Given the following data:

31.5 32.9 33.0 28.6 37.2 43.3 45.9 37.2 68.8 36.2 35.5 31.5 32.9 33.0 28.6 37.2 43.3 45.9 37.2 68.8 36.2 35.5 40.5 37.2 45.3 36.1 45.5 42.3 33.3 30.3 37.2 45.5 54.3 37.2 49.8 32.1 39.3 40.3 44.2 28.4 46.0 47.2 32.8 32.2 38.5 44.5 44.6 40.9 29.5 41.3 35.4

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29.5_______1___________1.96

30.3_______1___________1.96

31.5_______2___________3.92

32.1_______1____________1.96

32.2_______1___________1.96

32.8_______1___________1.96

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33________2___________3.92

33.3_______1___________1.96

35.4_______1___________1.96

35.5_______2___________3.92

36.1________1___________1.96

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39.3_______1____________1.96

40.3_______1____________1.96

40.5_______1____________ 1.96

40.9_______1____________1.96

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42.3______1_____________1.96

43.3______2____________ 3.92

44.2______1 _____________1.96

44.5______1 _____________1.96

44.6_____ 1 ______________1.96

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45.9_____2 ______3.92

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47.2_____1 _______1.96

49.8_____1 _______1.96

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Lower outlier = Q1 - (1.5 × IQR)

Upper outlier = Q3 + (1.5 × IQR)

IQR = Interquartile range ;

Q1 = 1/4(n+1)th term

Q3 = 3/4(n+1)th term

IQR = Q3 - Q1

n = number of observations = 51

Q1 = (51 + 1)/4= 52/4 = 13 th term = 33

Q3 = 3(51 + 1) /4 = 156/4 = 39th term = 44.5

IQR = 44.5 - 33 = 11.5

LOWER OUTLIER = 33 - (1.5*11.5) = 33 - 17.25 = entries < 15.75

UPPER OUTLIER = 44.5 + (1.5*11.5) = 44.5 + 17.25 = 61.75

Entries > 61.75

7 0
3 years ago
0.7 , 2/3 , 5/8 , 65% in least to greatest
egoroff_w [7]

Answer:

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Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
For the trapezoid ABCD E and F are the midpoints of
lawyer [7]

Answer:

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Step-by-step explanation:

we know that

The <u><em>Trapezoid Mid-segment Theorem</em></u>. states that the length of the mid-segment is equal to the sum of the base lengths divided by two.

so

EF=\frac{BC+AD}{2}

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EF=\frac{b+d}{2}\ units

6 0
3 years ago
Y is inversely proportional to 7I+x.<br>When x = 8, y = 2.<br>Find y when x= 15.​
const2013 [10]

I am taking 7I+x to  mean 71+ x.

Answer:  y=1.837

Step-by-step explanation:

Step 1

Let y is inversely proportional to 7I+x be  mathematically be written as

y ∝ 1/7I+x

Introducing our proportionality of constant , K we have that

y ∝ 1/7I+x

y =K 1/7I+x

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Step 2

so when x= 8, and y =2,  k becomes

y= K/ 7I+x

k=  y x (7I+x)

=2 x (71 + 8)

2x 79

=158

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y= K/ 7I+x

y= 158/  71 + 15

y=158/86

y=1.837

6 0
3 years ago
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