All categories

3 years ago

Jason Aldeen bought a house for $275,000. He made a down payment of 15%. The interest rate is 4.2% for 15 years.

Mathematics

1 answer:

Tpy6a [65]3 years ago

3 0

Answer:

Step-by-step explanation:

Jason's down payment= $41250

Amount he needs to borrow is

275000-41250 = $233750

Jason's monthly payment would be

248476.25/180 = $1380.42

The original cost of the house that Jason Aldeen bought is $275,000. He made a down payment of 15%. This means he paid 15% of the original cost of the house. Therefore,

Jason's down payment is 15% of $275000

= 15/100 × 275000 =0.15×275000

=$41250

Since Jason's down payment is smaller than the original cost of the house, he would need to borrow.

Amount he needs to borrow is

275000-41250 = $233750

If Jason borrows $233750 at a rate of 4.2% for 15 years

Total interest on $233750 for 15 years will be

= (233750×4.2×15) /100

= 14726250/100 = $14726.25

Total amount to be paid for 15 years will be amount borrowed + interest

=233750 + 14726.25 = $248476.25

Converting 15 years to months,

15 × 12 months = 180 months.

Jason's monthly payment would be

248476.25/180 = $1380.42

You might be interested in

What is (14,-12) translated 6 units left

marissa [1.9K]

Going to the right or left when doing translation effects the x coordinate. In this case, the x coordinate is 14. Since we are moving 6 units to the left, we must subtract 6 from 14. Moving to the left is negative and moving to the right is positive.

14 - 6 = 8

The answer is (8,-12)

7 0

4 years ago

Find the distance between the points (7,-5) and (2, -5).

vazorg [7]

Answer:

15.62 units.

Step-by-step explanation:

To commence with, find for the vector.

Points = (7,-5) and (2,-5)

7 + 2

-5 + -5

-10

Vector = 12

-10

Magnitude = y² + x²

Points = (12,-10)

-10² + 12²

100 + 144

244

Square root of 244 is 15.62

Therefore, the distance between the points is 15.62 units.

Hope it helps.

3 0

3 years ago

Read 2 more answers

4.) What is the exact value of sinθ when θ lies in Quadrant II and cosθ=−513

dimaraw [331]

Answer:

Part 4) $sin(\theta)=\frac{12}{13}$

Part 10) The angle of elevation is $40.36\°$

Part 11) The angle of depression is $78.61\°$

Part 12) $arcsin(0.5)=30\°$ or $arcsin(0.5)=150\°$

Part 13) $-45\°$ or $225\°$

Step-by-step explanation:

Part 4) we have that

$cos(\theta)=-\frac{5}{13}$

The angle theta lies in Quadrant II

The sine of angle theta is positive

Remember that

$sin^{2}(\theta)+ cos^{2}(\theta)=1$

substitute the given value

$sin^{2}(\theta)+(-\frac{5}{13})^{2}=1$

$sin^{2}(\theta)+(\frac{25}{169})=1$

$sin^{2}(\theta)=1-(\frac{25}{169})$

$sin^{2}(\theta)=(\frac{144}{169})$

$sin(\theta)=\frac{12}{13}$

Part 10)

Let

$\theta$ ----> angle of elevation

we know that

$tan(\theta)=\frac{85}{100}$ ----> opposite side angle theta divided by adjacent side angle theta

$\theta=arctan(\frac{85}{100})=40.36\°$

Part 11)

Let

$\theta$ ----> angle of depression

we know that

$sin(\theta)=\frac{5,389-2,405}{3,044}$ ----> opposite side angle theta divided by hypotenuse

$sin(\theta)=\frac{2,984}{3,044}$

$\theta=arcsin(\frac{2,984}{3,044})=78.61\°$

Part 12) What is the exact value of arcsin(0.5)?

Remember that

$sin(30\°)=0.5$

therefore

$arcsin(0.5)$ -----> has two solutions

$arcsin(0.5)=30\°$ ----> I Quadrant

$arcsin(0.5)=180\°-30\°=150\°$ ----> II Quadrant

Part 13) What is the exact value of $arcsin(-\frac{\sqrt{2}}{2})$

The sine is negative

The angle lies in Quadrant III or Quadrant IV

Remember that

$sin(45\°)=\frac{\sqrt{2}}{2}$

therefore

$arcsin(-\frac{\sqrt{2}}{2})$ ----> has two solutions

$arcsin(-\frac{\sqrt{2}}{2})=-45\°$ ----> IV Quadrant

$arcsin(-\frac{\sqrt{2}}{2})=180\°+45\°=225\°$ ----> III Quadrant

5 0

3 years ago

Write 2/3 of 4 as a fraction

eduard

2 / 3 of 4 = ( 2 x 4 ) / 3 = 8 / 3 ;

7 0

3 years ago

Please solve this equations y=6x²-5,y=17x-6/x

Amiraneli [1.4K]

Answer:

$x=3, y = 49\\x=0.5, y = -3.5\\x=-0.67, y = -2.31$

Step-by-step explanation:

$y=6x^2-5\\y=17x-\frac{6}{x}$

Let's substitute the first equation into the second one.

$6x^2-5=17x-\frac{6}{x}$

$6x^3-17x^2-5x+6=0$ - Multiply by $x$ and bring all the terms to one side.

I'll use my graphical calculator to solve this but you could factor:

$x=3\\x=0.5\\x=-0.67$ (All rounded to 2 decimal places)

Now we can substitute these $x$ values into an equation for $y$ .

$y=6x^2 - 5$

$x=3, y = 49\\x=0.5, y = -3.5\\x=-0.67, y = -2.31$

5 0

3 years ago