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MakcuM [25]
3 years ago
11

A triangle has sides with lengths of 12 meters, 17 meters, and 20 meters. Is it a right triangle?

Mathematics
1 answer:
nadezda [96]3 years ago
5 0

Answer:

This is not a right angled triangle.

Step-by-step explanation:

12^2+17^2=433

Square root of 433 is not 20 and hence this is not a right angled triangle.

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Answer:

A. 5

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21 cans of dog food.

She gives 21/3, or 7 cans to her neighbor.

She now has 21 - 7, or 14 cans for her puppy.

Her puppy eats 4/7 cans a day.

14 \times \frac{4}{7} =2\times 4= \boxed{\bf{8}}

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3 years ago
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Maslowich

Answer:

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Step-by-step explanation:

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3 years ago
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Use the Law of Sines to find the missing angle of the triangle.
Natasha2012 [34]

Answer:

m∠B = 70.0° (nearest tenth)

Step-by-step explanation:

<u>Sine Rule for Angles</u>

\sf \dfrac{\sin A}{a}=\dfrac{\sin B}{b}=\dfrac{\sin C}{c}

(where A, B and C are the angles and a, b and c are the sides opposite the angles)

Given:

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  • c = 19
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Substituting the given values into the formula to find m∠C:

\implies \sf \dfrac{\sin 40^{\circ}}{13}=\dfrac{\sin C}{19}

\implies \sf \sin C=\dfrac{19\sin 40^{\circ}}{13}

\implies \sf C=\sin^{-1}\left(\dfrac{19\sin 40^{\circ}}{13}\right)

\implies \sf m \angle C=69.96086904^{\circ}

Interior angles of a triangle sum to 180°

\implies \sf m \angle A+ m \angle B+m \angle C=180^{\circ}

\implies \sf 40^{\circ} + m \angle B+69.960...^{\circ}=180^{\circ}

\implies \sf m \angle B=70.03913...^{\circ}

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8 0
2 years ago
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Lady bird [3.3K]

Answer: n=3

Step-by-step explanation:

6n-10=8

6n=18

n=3

You start by adding 10 to both sides and then divide both sides by 6.

4 0
3 years ago
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