Only two more!!! 1/2
2 answers:
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Answer:
All solutions
Step-by-step explanation:
When solving by substitution, we will first set one equation equal to a variable, and then plug that value into the second equation as the variable. Here is what I mean;
x - 2y = 1
3x - 6y = 3
-
x = 1 + 2y
3x - 6y = 3
-
3(1 + 2y) - 6y = 3
3 + 6y - 6y = 3
3 = 3
[] Oh no! This doesn't work well. Let's graph it and see what is happening;
-> See attached
-> I have made the lines very thick so you can see the overlap, they are the same size in reality
The answer is all solutions because the graphs are exactly the same.
Have a nice day!
I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly.
- Heather
For this case we have the following linear function:
What we must do is equal the function to zero or equivalently, substitute the value of y = 0 in the given function.
We have then:
From here, we clear the value of x.
We have then:
Answer:
all real zeros of the function y = 2x-4 are:
x = 2
What we must do is equal the function to zero or equivalently, substitute the value of y = 0 in the given function.
We have then:
From here, we clear the value of x.
We have then:
Answer:
all real zeros of the function y = 2x-4 are:
x = 2