Answer:
a) 30.726m/s and b) 5.5549s
Step-by-step explanation:
a.) What was Chris Huber’s speed in meters per second(m/s)?
Given the distance and time, the formula to obtain the speed is
.
Applying this to our problem we have that
.
So, Chris Huber’s speed in meters per second(m/s) was 30.726m/s.
b) What was Whittingham’s time through the 200 m?
In a) we stated that . This formula implies that
.
First, observer that 
.
Then, Sam Whittingham speed was equal to Chris Huber’s speed plus 5.2777 m/s. So, 
Then, applying 1) we have that
So, Sam Whittingham’s time through the 200 m was 5.5549s.
Answer: Stephon can buy total 4 chips bag and 2 candy bar
Step-by-step explanation:Given as :
The money which Stephon has in his pocket = $ 12
The cost of one chips bag = $ 2.25
The cost of one candy bar = $ 1.50
The total number of items he can buy = 6
So, Let the number of chips bag he can buy = x
∴ The number of candy bar he can buy = 6 - x
Now, according to question
The number of chips bag×The cost of one chips bag + The number of candy bar×The cost of one candy bar = $ 12
Or, x × $ 2.25 + (6-x) × $ 1.50 = $ 12
Or, x × $ 2.25 + 9 - x × $ 1.50 = $ 12
or, x × $ 0.75 = 12 - 9
or, x = = 4
The number of chips bag he can buy = x = 4
And The number of candy bar he can buy = 6 - x = 6 - 4 = 2
Hence Stephon can buy total 4 chips bag and 2 candy bar .
Answer:
359
Step-by-step explanation:
6x3+18
18 to the second power is 324
10x3=30
30+5=35
324+35=359
